030_collections_Counter.md

030 - collections.Counter()

Problem

collections.Counter()

A counter is a container that stores elements as dictionary keys, and their counts are stored as dictionary values.

Sample Code

from collections import Counter

myList = [1,1,2,3,4,5,3,2,3,4,2,1,2,3]

print(Counter(myList))
print(Counter(myList).items())
print(Counter(myList).keys())
print(Counter(myList).values())

Counter({2: 4, 3: 4, 1: 3, 4: 2, 5: 1})
dict_items([(1, 3), (2, 4), (3, 4), (4, 2), (5, 1)])
dict_keys([1, 2, 3, 4, 5])
dict_values([3, 4, 4, 2, 1])

Task

Raghu is a shoe shop owner. His shop has X number of shoes.

He has a list containing the size of each shoe he has in his shop.

There are N number of customers who are willing to pay x_i amount of money only if they get the shoe of their desired size.

Your task is to compute how much money Raghu earned.

Input Format

The first line contains X, the number of shoes.

The second line contains the space separated list of all the shoe sizes in the shop.

The third line contains N, the number of customers.

The next N lines contain the space separated values of the shoe size desired by the customer and x_i, the price of the shoe.

Constraints

• 0 < X < 10³
• 0 < N < 10³
• 20 < x_i < 100
• 2 < shoe size < 20

Output Format

Print the amount of money earned by Raghu.

Sample Input

10
2 3 4 5 6 8 7 6 5 18
6
6 55
6 45
6 55
4 40
18 60
10 50

Sample Output

200

Explanation

Customer 1 : Purchased size 6 shoe for $55
Customer 2 : Purchased size 6 shoe for $45
Customer 3 : Size 6 no longer available, so no purchase
Customer 4 : Purchased size 4 shoes for $40
Customer 5 : Purchased size 18 show for $60
Customer 6 : Size 10 not available, so no purchase

Total money earned = 55 + 45 + 40 + 60 = $200

Solution

from collections import Counter


def earned(sales, stock):
    earned = 0

    for i in range(sales):
        sale = input().split(" ")
        shoe, price = sale[0], int(sale[1])

        if shoe in stock and stock[shoe] >= 1:
            earned += price
            stock[shoe] -= 1
        else:
            continue

    return earned


stock_len = int(input())
stock = dict(Counter([i for i in input().split(" ")]))
sales = int(input())



print(earned(sales, stock))