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feat: add solutions to lc problems: No.1159,1164
* No.1159.Market Analysis II * No.1164.Product Price at a Given Date
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6 files changed

+162
-4
lines changed

‎solution/1100-1199/1159.Market Analysis II/README.md

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Original file line numberDiff line numberDiff line change
@@ -114,7 +114,30 @@ id为 4 的用户的查询结果是 no，因为他卖出的第二件商品的品
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### **SQL**
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```sql
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# Write your MySQL query statement below
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select
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u.user_id as seller_id,
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case
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when u.favorite_brand = i.item_brand then 'yes'
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else 'no'
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end as 2nd_item_fav_brand
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from
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users u
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left join (
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select
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order_date,
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item_id,
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seller_id,
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rank() over(
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partition by seller_id
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order by
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order_date
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) as rk
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from
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orders
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) o on u.user_id = o.seller_id
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and o.rk = 2
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left join items i on o.item_id = i.item_id;
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```
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<!-- tabs:end -->

‎solution/1100-1199/1159.Market Analysis II/README_EN.md

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Original file line numberDiff line numberDiff line change
@@ -115,7 +115,30 @@ The answer for the user with id 4 is no because the brand of their second sold i
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### **SQL**
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```sql
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# Write your MySQL query statement below
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select
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u.user_id as seller_id,
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case
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when u.favorite_brand = i.item_brand then 'yes'
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else 'no'
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end as 2nd_item_fav_brand
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from
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users u
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left join (
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select
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order_date,
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item_id,
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seller_id,
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rank() over(
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partition by seller_id
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order by
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order_date
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) as rk
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from
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orders
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) o on u.user_id = o.seller_id
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and o.rk = 2
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left join items i on o.item_id = i.item_id;
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```
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<!-- tabs:end -->

‎solution/1100-1199/1159.Market Analysis II/Solution.sql

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@@ -0,0 +1,24 @@
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# Write your MySQL query statement below
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select
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u.user_id as seller_id,
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case
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when u.favorite_brand = i.item_brand then 'yes'
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else 'no'
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end as 2nd_item_fav_brand
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from
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users u
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left join (
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select
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order_date,
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item_id,
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seller_id,
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rank() over(
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partition by seller_id
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order by
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order_date
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) as rk
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from
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orders
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) o on u.user_id = o.seller_id
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and o.rk = 2
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left join items i on o.item_id = i.item_id;

‎solution/1100-1199/1164.Product Price at a Given Date/README.md

+30-1
Original file line numberDiff line numberDiff line change
@@ -62,7 +62,36 @@ Products</code> 表:
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### **SQL**
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```sql
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# Write your MySQL query statement below
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select
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p1.product_id product_id,
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ifnull(p2.price, 10) price
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from
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(
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select
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distinct(product_id) product_id
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from
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Products
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) p1
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left join (
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select
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t1.product_id,
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t1.new_price price
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from
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Products t1
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join (
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select
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product_id,
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max(change_date) change_date
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from
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Products
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where
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change_date <= '2019-08-16'
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group by
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product_id
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) t2 on t1.product_id = t2.product_id
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and t1.change_date = t2.change_date
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) p2 on p1.product_id = p2.product_id;
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```
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<!-- tabs:end -->

‎solution/1100-1199/1164.Product Price at a Given Date/README_EN.md

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Original file line numberDiff line numberDiff line change
@@ -58,7 +58,36 @@ Products table:
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### **SQL**
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```sql
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# Write your MySQL query statement below
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select
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p1.product_id product_id,
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ifnull(p2.price, 10) price
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from
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(
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select
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distinct(product_id) product_id
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from
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Products
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) p1
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left join (
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select
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t1.product_id,
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t1.new_price price
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from
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Products t1
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join (
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select
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product_id,
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max(change_date) change_date
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from
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Products
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where
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change_date <= '2019-08-16'
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group by
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product_id
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) t2 on t1.product_id = t2.product_id
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and t1.change_date = t2.change_date
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) p2 on p1.product_id = p2.product_id;
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```
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<!-- tabs:end -->

‎solution/1100-1199/1164.Product Price at a Given Date/Solution.sql

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# Write your MySQL query statement below
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select
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p1.product_id product_id,
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ifnull(p2.price, 10) price
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from
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(
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select
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distinct(product_id) product_id
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from
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Products
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) p1
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left join (
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select
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t1.product_id,
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t1.new_price price
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from
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Products t1
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join (
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select
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product_id,
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max(change_date) change_date
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from
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Products
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where
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change_date <= '2019-08-16'
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group by
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product_id
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) t2 on t1.product_id = t2.product_id
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and t1.change_date = t2.change_date
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) p2 on p1.product_id = p2.product_id;

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