feature: add golang solution for leetcode 1002

Author: hzliangbin

solution/1000-1099/1002.Find Common Characters/README.md

@@ -54,8 +54,46 @@
 
 ```
 
-### **...**
-```
+### **Go**
+```go
+func commonChars(A []string) []string {
+    if len(A) == 0 {
+        return []string{}
+    }
+    res := make([]int, 26)
+    //以第一个字符串为基准，先统计出现次数
+    for _, c := range A[0] {
+        res[c - 'a']++
+    }
+    for i := 1; i < len(A); i++ {
+        tmp := make([]int, 26)
+        //统计后续每个字符串的字符出现次数
+        for _, c := range A[i] {
+            tmp[c - 'a']++
+        }
+        //比较，取小
+        for j := 0; j < 26; j++ {
+            res[j] = getMin(res[j], tmp[j])
+        }
+    }
+    //遍历res,取出字符转换为string数组元素
+    result := make([]string,0)
+    for i := 0; i < len(res); i++ {
+        if res[i] > 0 {
+            for j := 0; j < res[i]; j++ {
+                result = append(result, string('a' + i))
+            }
+        }
+    }
+    return result
+}
+
+func getMin(a,b int) int {
+    if a > b{
+        return b
+    }
+    return a
+}
 
 ```
 

solution/1000-1099/1002.Find Common Characters/Solution.go

@@ -0,0 +1,43 @@
+func commonChars(A []string) []string {
+    if len(A) == 0 {
+        return []string{}
+    }
+    res := make([]int, 26)
+    //以第一个字符串为基准，先统计出现次数
+    for _, c := range A[0] {
+        res[c - 'a']++
+    }
+    for i := 1; i < len(A); i++ {
+        tmp := make([]int, 26)
+        //统计后续每个字符串的字符出现次数
+        for _, c := range A[i] {
+            tmp[c - 'a']++
+        }
+        //比较，取小
+        for j := 0; j < 26; j++ {
+            res[j] = getMin(res[j], tmp[j])
+        }
+    }
+    //遍历res,取出字符转换为string数组元素
+    result := make([]string,0)
+    for i := 0; i < len(res); i++ {
+        if res[i] > 0 {
+            for j := 0; j < res[i]; j++ {
+                result = append(result, string('a' + i))
+            }
+        }
+    }
+    return result
+}
+
+func getMin(a,b int) int {
+    if a > b{
+        return b
+    }
+    return a
+}
+
+
+
+
+