feat: add solutions to lc problems: No.1119,1683,1757,1821

Author: yanglbme

solution/1100-1199/1119.Remove Vowels from a String/README.md

@@ -43,15 +43,31 @@
 <!-- 这里可写当前语言的特殊实现逻辑 -->
 
 ```python
-
+class Solution:
+    def removeVowels(self, s: str) -> str:
+        res = []
+        for c in s:
+            if c not in {'a', 'e', 'i', 'o', 'u'}:
+                res.append(c)
+        return ''.join(res)
 ```
 
 ### **Java**
 
 <!-- 这里可写当前语言的特殊实现逻辑 -->
 
 ```java
-
+class Solution {
+    public String removeVowels(String s) {
+        StringBuilder res = new StringBuilder();
+        for (char c : s.toCharArray()) {
+            if (!(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u')) {
+                res.append(c);
+            }
+        }
+        return res.toString();
+    }
+}
 ```
 
 ### **...**

solution/1100-1199/1119.Remove Vowels from a String/README_EN.md

@@ -37,13 +37,29 @@
 ### **Python3**
 
 ```python
-
+class Solution:
+    def removeVowels(self, s: str) -> str:
+        res = []
+        for c in s:
+            if c not in {'a', 'e', 'i', 'o', 'u'}:
+                res.append(c)
+        return ''.join(res)
 ```
 
 ### **Java**
 
 ```java
-
+class Solution {
+    public String removeVowels(String s) {
+        StringBuilder res = new StringBuilder();
+        for (char c : s.toCharArray()) {
+            if (!(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u')) {
+                res.append(c);
+            }
+        }
+        return res.toString();
+    }
+}
 ```
 
 ### **...**

solution/1100-1199/1119.Remove Vowels from a String/Solution.java

@@ -0,0 +1,11 @@
+class Solution {
+    public String removeVowels(String s) {
+        StringBuilder res = new StringBuilder();
+        for (char c : s.toCharArray()) {
+            if (!(c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u')) {
+                res.append(c);
+            }
+        }
+        return res.toString();
+    }
+}

solution/1100-1199/1119.Remove Vowels from a String/Solution.py

@@ -0,0 +1,7 @@
+class Solution:
+    def removeVowels(self, s: str) -> str:
+        res = []
+        for c in s:
+            if c not in {'a', 'e', 'i', 'o', 'u'}:
+                res.append(c)
+        return ''.join(res)

solution/1600-1699/1683.Invalid Tweets/README.md

@@ -45,17 +45,27 @@ tweet_id 是这个表的主键。
 推文 2 的长度 length = 32。该推文是无效的。
 </pre>
 
-
 ## 解法
 
 <!-- 这里可写通用的实现逻辑 -->
 
+- `CHAR_LENGTH(str)`: 中文、数字、字母都是 1 字节
+- `LENGTH(str)`:
+  - utf8: 中文 3 字节，数字、字母 1 字节
+  - gbk: 中文 2 字节，数字、字母 1 字节
+
 <!-- tabs:start -->
 
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+    tweet_id
+FROM
+    Tweets
+WHERE
+    CHAR_LENGTH(content) > 15;
 ```
 
-<!-- tabs:end -->
+<!-- tabs:end -->

solution/1600-1699/1683.Invalid Tweets/README_EN.md

@@ -54,7 +54,13 @@ Tweet 2 has length = 32. It is an invalid tweet.
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+    tweet_id
+FROM
+    Tweets
+WHERE
+    CHAR_LENGTH(content) > 15;
 ```
 
 <!-- tabs:end -->

solution/1600-1699/1683.Invalid Tweets/Solution.sql

@@ -0,0 +1,7 @@
+# Write your MySQL query statement below
+SELECT
+    tweet_id
+FROM
+    Tweets
+WHERE
+    CHAR_LENGTH(content) > 15;

solution/1700-1799/1757.Recyclable and Low Fat Products/README.md

@@ -59,7 +59,14 @@ Result 表：
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+    product_id
+FROM
+    Products
+WHERE
+    low_fats = 'Y'
+AND recyclable = 'Y';
 ```
 
 <!-- tabs:end -->

solution/1700-1799/1757.Recyclable and Low Fat Products/README_EN.md

@@ -57,7 +57,14 @@ Only products 1 and 3 are both low fat and recyclable.
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+    product_id
+FROM
+    Products
+WHERE
+    low_fats = 'Y'
+AND recyclable = 'Y';
 ```
 
 <!-- tabs:end -->

solution/1700-1799/1757.Recyclable and Low Fat Products/Solution.sql

@@ -0,0 +1,8 @@
+# Write your MySQL query statement below
+SELECT
+    product_id
+FROM
+    Products
+WHERE
+    low_fats = 'Y'
+AND recyclable = 'Y';

solution/1800-1899/1821.Find Customers With Positive Revenue this Year/README.md

@@ -70,7 +70,14 @@ Result table:
 <!-- 这里可写当前语言的特殊实现逻辑 -->
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+    customer_id
+FROM
+    Customers
+WHERE
+    year = '2021'
+AND revenue > 0;
 ```
 
 <!-- tabs:end -->

solution/1800-1899/1821.Find Customers With Positive Revenue this Year/README_EN.md

@@ -65,7 +65,14 @@ Thus only customers 1 and 4 have postive revenue in year 2021.</pre>
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+    customer_id
+FROM
+    Customers
+WHERE
+    year = '2021'
+AND revenue > 0;
 ```
 
 <!-- tabs:end -->

solution/1800-1899/1821.Find Customers With Positive Revenue this Year/Solution.sql

@@ -0,0 +1,8 @@
+# Write your MySQL query statement below
+SELECT
+    customer_id
+FROM
+    Customers
+WHERE
+    year = '2021'
+AND revenue > 0;