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43 | 43 |
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44 | 44 | <!-- 这里可写通用的实现逻辑 -->
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45 | 45 |
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| 46 | +**方法一:字符串哈希** |
| 47 | + |
46 | 48 | <!-- tabs:start -->
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47 | 49 |
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48 | 50 | ### **Python3**
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49 | 51 |
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50 | 52 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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51 | 53 |
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52 | 54 | ```python
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53 |
| - |
| 55 | +class Solution: |
| 56 | + def distinctEchoSubstrings(self, text: str) -> int: |
| 57 | + def get(l, r): |
| 58 | + return (h[r] - h[l - 1] * p[r - l + 1]) % mod |
| 59 | + |
| 60 | + n = len(text) |
| 61 | + base = 131 |
| 62 | + mod = int(1e9) + 7 |
| 63 | + h = [0] * (n + 10) |
| 64 | + p = [1] * (n + 10) |
| 65 | + for i, c in enumerate(text): |
| 66 | + t = ord(c) - ord('a') + 1 |
| 67 | + h[i + 1] = (h[i] * base) % mod + t |
| 68 | + p[i + 1] = (p[i] * base) % mod |
| 69 | + vis = set() |
| 70 | + for i in range(n - 1): |
| 71 | + for j in range(i + 1, n, 2): |
| 72 | + k = (i + j) >> 1 |
| 73 | + a = get(i + 1, k + 1) |
| 74 | + b = get(k + 2, j + 1) |
| 75 | + if a == b: |
| 76 | + vis.add(a) |
| 77 | + return len(vis) |
54 | 78 | ```
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55 | 79 |
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56 | 80 | ### **Java**
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57 | 81 |
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58 | 82 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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59 | 83 |
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60 | 84 | ```java
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| 85 | +class Solution { |
| 86 | + private long[] h; |
| 87 | + private long[] p; |
| 88 | + |
| 89 | + public int distinctEchoSubstrings(String text) { |
| 90 | + int n = text.length(); |
| 91 | + int base = 131; |
| 92 | + h = new long[n + 10]; |
| 93 | + p = new long[n + 10]; |
| 94 | + p[0] = 1; |
| 95 | + for (int i = 0; i < n; ++i) { |
| 96 | + int t = text.charAt(i) - 'a' + 1; |
| 97 | + h[i + 1] = h[i] * base + t; |
| 98 | + p[i + 1] = p[i] * base; |
| 99 | + } |
| 100 | + Set<Long> vis = new HashSet<>(); |
| 101 | + for (int i = 0; i < n - 1; ++i) { |
| 102 | + for (int j = i + 1; j < n; j += 2) { |
| 103 | + int k = (i + j) >> 1; |
| 104 | + long a = get(i + 1, k + 1); |
| 105 | + long b = get(k + 2, j + 1); |
| 106 | + if (a == b) { |
| 107 | + vis.add(a); |
| 108 | + } |
| 109 | + } |
| 110 | + } |
| 111 | + return vis.size(); |
| 112 | + } |
| 113 | + |
| 114 | + private long get(int i, int j) { |
| 115 | + return h[j] - h[i - 1] * p[j - i + 1]; |
| 116 | + } |
| 117 | +} |
| 118 | +``` |
| 119 | + |
| 120 | +### **C++** |
| 121 | + |
| 122 | +```cpp |
| 123 | +typedef unsigned long long ull; |
| 124 | + |
| 125 | +class Solution { |
| 126 | +public: |
| 127 | + int distinctEchoSubstrings(string text) { |
| 128 | + int n = text.size(); |
| 129 | + int base = 131; |
| 130 | + vector<ull> p(n + 10); |
| 131 | + vector<ull> h(n + 10); |
| 132 | + p[0] = 1; |
| 133 | + for (int i = 0; i < n; ++i) |
| 134 | + { |
| 135 | + int t = text[i] - 'a' + 1; |
| 136 | + p[i + 1] = p[i] * base; |
| 137 | + h[i + 1] = h[i] * base + t; |
| 138 | + } |
| 139 | + unordered_set<ull> vis; |
| 140 | + for (int i = 0; i < n - 1; ++i) |
| 141 | + { |
| 142 | + for (int j = i + 1; j < n; j += 2) |
| 143 | + { |
| 144 | + int k = (i + j) >> 1; |
| 145 | + ull a = get(i + 1, k + 1, p, h); |
| 146 | + ull b = get(k + 2, j + 1, p, h); |
| 147 | + if (a == b) vis.insert(a); |
| 148 | + } |
| 149 | + } |
| 150 | + return vis.size(); |
| 151 | + } |
| 152 | + |
| 153 | + ull get(int l, int r, vector<ull>& p, vector<ull>& h) { |
| 154 | + return h[r] - h[l - 1] * p[r - l + 1]; |
| 155 | + } |
| 156 | +}; |
| 157 | +``` |
61 | 158 |
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| 159 | +### **Go** |
| 160 | + |
| 161 | +```go |
| 162 | +func distinctEchoSubstrings(text string) int { |
| 163 | + n := len(text) |
| 164 | + base := 131 |
| 165 | + h := make([]int, n+10) |
| 166 | + p := make([]int, n+10) |
| 167 | + p[0] = 1 |
| 168 | + for i, c := range text { |
| 169 | + t := int(c-'a') + 1 |
| 170 | + p[i+1] = p[i] * base |
| 171 | + h[i+1] = h[i]*base + t |
| 172 | + } |
| 173 | + get := func(l, r int) int { |
| 174 | + return h[r] - h[l-1]*p[r-l+1] |
| 175 | + } |
| 176 | + vis := map[int]bool{} |
| 177 | + for i := 0; i < n-1; i++ { |
| 178 | + for j := i + 1; j < n; j += 2 { |
| 179 | + k := (i + j) >> 1 |
| 180 | + a, b := get(i+1, k+1), get(k+2, j+1) |
| 181 | + if a == b { |
| 182 | + vis[a] = true |
| 183 | + } |
| 184 | + } |
| 185 | + } |
| 186 | + return len(vis) |
| 187 | +} |
62 | 188 | ```
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63 | 189 |
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64 | 190 | ### **...**
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