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34 | 34 | <li><code>0 <= grid[i][j] <= 100</code></li>
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35 | 35 | </ul>
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36 | 36 |
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37 |
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38 | 37 | ## Solutions
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39 | 38 |
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40 | 39 | <!-- tabs:start -->
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41 | 40 |
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42 | 41 | ### **Python3**
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43 | 42 |
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44 | 43 | ```python
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45 |
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| 44 | +class Solution: |
| 45 | + def minPathSum(self, grid: List[List[int]]) -> int: |
| 46 | + m, n = len(grid), len(grid[0]) |
| 47 | + dp = [[grid[0][0]] * n for _ in range(m)] |
| 48 | + for i in range(1, m): |
| 49 | + dp[i][0] = dp[i - 1][0] + grid[i][0] |
| 50 | + for j in range(1, n): |
| 51 | + dp[0][j] = dp[0][j - 1] + grid[0][j] |
| 52 | + for i in range(1, m): |
| 53 | + for j in range(1, n): |
| 54 | + dp[i][j] = min(dp[i - 1][j], dp[i][j - 1]) + grid[i][j] |
| 55 | + return dp[m - 1][n - 1] |
46 | 56 | ```
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47 | 57 |
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48 | 58 | ### **Java**
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49 | 59 |
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50 | 60 | ```java
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| 61 | +class Solution { |
| 62 | + public int minPathSum(int[][] grid) { |
| 63 | + int m = grid.length, n = grid[0].length; |
| 64 | + int[][] dp = new int[m][n]; |
| 65 | + dp[0][0] = grid[0][0]; |
| 66 | + for (int i = 1; i < m; ++i) { |
| 67 | + dp[i][0] = dp[i - 1][0] + grid[i][0]; |
| 68 | + } |
| 69 | + for (int j = 1; j < n; ++j) { |
| 70 | + dp[0][j] = dp[0][j - 1] + grid[0][j]; |
| 71 | + } |
| 72 | + for (int i = 1; i < m; ++i) { |
| 73 | + for (int j = 1; j < n; ++j) { |
| 74 | + dp[i][j] = Math.min(dp[i - 1][j], dp[i][j - 1]) + grid[i][j]; |
| 75 | + } |
| 76 | + } |
| 77 | + return dp[m - 1][n - 1]; |
| 78 | + } |
| 79 | +} |
| 80 | +``` |
51 | 81 |
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| 82 | +### **C++** |
| 83 | + |
| 84 | +```cpp |
| 85 | +class Solution { |
| 86 | +public: |
| 87 | + int minPathSum(vector<vector<int>>& grid) { |
| 88 | + int m = grid.size(), n = grid[0].size(); |
| 89 | + vector<vector<int>> dp(m, vector<int>(n, grid[0][0])); |
| 90 | + for (int i = 1; i < m; ++i) { |
| 91 | + dp[i][0] = dp[i - 1][0] + grid[i][0]; |
| 92 | + } |
| 93 | + for (int j = 1; j < n; ++j) { |
| 94 | + dp[0][j] = dp[0][j - 1] + grid[0][j]; |
| 95 | + } |
| 96 | + for (int i = 1; i < m; ++i) { |
| 97 | + for (int j = 1; j < n; ++j) { |
| 98 | + dp[i][j] = min(dp[i - 1][j], dp[i][j - 1]) + grid[i][j]; |
| 99 | + } |
| 100 | + } |
| 101 | + return dp[m - 1][n - 1]; |
| 102 | + } |
| 103 | +}; |
52 | 104 | ```
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53 | 105 |
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54 | 106 | ### **...**
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