Skip to content

Latest commit

 

History

History
98 lines (50 loc) · 2.91 KB

File metadata and controls

98 lines (50 loc) · 2.91 KB

中文文档

Description

Compare two version numbers version1 and version2.

If version1 > version2 return 1; if version1 < version2 return -1;otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.

The . character does not represent a decimal point and is used to separate number sequences.

For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

You may assume the default revision number for each level of a version number to be 0. For example, version number 3.4 has a revision number of 3 and 4 for its first and second level revision number. Its third and fourth level revision number are both 0.

 

Example 1:

Input: version1 = "0.1", version2 = "1.1"

Output: -1

Example 2:

Input: version1 = "1.0.1", version2 = "1"

Output: 1

Example 3:

Input: version1 = "7.5.2.4", version2 = "7.5.3"

Output: -1

Example 4:

Input: version1 = "1.01", version2 = "1.001"

Output: 0

Explanation: Ignoring leading zeroes, both “01” and “001" represent the same number “1”

Example 5:

Input: version1 = "1.0", version2 = "1.0.0"

Output: 0

Explanation: The first version number does not have a third level revision number, which means its third level revision number is default to "0"

 

Note:

  1. Version strings are composed of numeric strings separated by dots . and this numeric strings may have leading zeroes.
  2. Version strings do not start or end with dots, and they will not be two consecutive dots.

Solutions

Python3

Java

...