Given a string containing just the characters '('
, ')'
, '{'
, '}'
, '['
and ']'
, determine if the input string is valid.
An input string is valid if:
- Open brackets must be closed by the same type of brackets.
- Open brackets must be closed in the correct order.
Note that an empty string is also considered valid.
Example 1:
Input: "()" Output: true
Example 2:
Input: "()[]{}" Output: true
Example 3:
Input: "(]" Output: false
Example 4:
Input: "([)]" Output: false
Example 5:
Input: "{[]}" Output: true
class Solution:
def isValid(self, s: str) -> bool:
if not s:
return True
helper = []
for c in s:
if c in '([{':
helper.append(c)
else:
if len(helper) == 0 or (helper.pop() + c) not in ["()", "[]", "{}"]:
return False
return len(helper) == 0
class Solution {
public boolean isValid(String s) {
if (s == null || s == "") {
return true;
}
char[] chars = s.toCharArray();
Stack<Character> helper = new Stack<>();
for (char c : chars) {
boolean isLeft = c == '(' || c == '[' || c == '{';
if (isLeft) {
helper.push(c);
} else {
if (helper.isEmpty() || !match(helper.pop(), c)) {
return false;
}
}
}
return helper.isEmpty();
}
private boolean match(char left, char right) {
return (left == '(' && right == ')')
|| (left == '[' && right == ']')
|| (left == '{' && right == '}');
}
}