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Description

Given a binary search tree (BST) with duplicates, find all the mode(s) (the most frequently occurred element) in the given BST.

Assume a BST is defined as follows:

    <li>The left subtree of a node contains only nodes with keys <b>less than or equal to</b> the node&#39;s key.</li>
    
    <li>The right subtree of a node contains only nodes with keys <b>greater than or equal to</b> the node&#39;s key.</li>
    
    <li>Both the left and right subtrees must also be binary search trees.</li>
    

 

For example:

Given BST [1,null,2,2],

   1

    \

     2

    /

   2

 

return [2].

Note: If a tree has more than one mode, you can return them in any order.

Follow up: Could you do that without using any extra space? (Assume that the implicit stack space incurred due to recursion does not count).

Solutions

Python3

Java

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