使用队列实现栈的下列操作:
- push(x) -- 元素 x 入栈
- pop() -- 移除栈顶元素
- top() -- 获取栈顶元素
- empty() -- 返回栈是否为空
注意:
- 你只能使用队列的基本操作-- 也就是
push to back
,peek/pop from front
,size
, 和is empty
这些操作是合法的。 - 你所使用的语言也许不支持队列。 你可以使用 list 或者 deque(双端队列)来模拟一个队列 , 只要是标准的队列操作即可。
- 你可以假设所有操作都是有效的(例如, 对一个空的栈不会调用 pop 或者 top 操作)。
class MyStack:
def __init__(self):
"""
Initialize your data structure here.
"""
self.q = []
def push(self, x: int) -> None:
"""
Push element x onto stack.
"""
self.q.append(x)
n = len(self.q)
for i in range(1, n):
self.q.append(self.q.pop(0))
def pop(self) -> int:
"""
Removes the element on top of the stack and returns that element.
"""
return self.q.pop(0)
def top(self) -> int:
"""
Get the top element.
"""
return self.q[0]
def empty(self) -> bool:
"""
Returns whether the stack is empty.
"""
return len(self.q) == 0
# Your MyStack object will be instantiated and called as such:
# obj = MyStack()
# obj.push(x)
# param_2 = obj.pop()
# param_3 = obj.top()
# param_4 = obj.empty()
class MyStack {
private Deque<Integer> q;
/** Initialize your data structure here. */
public MyStack() {
q = new ArrayDeque<>();
}
/** Push element x onto stack. */
public void push(int x) {
q.offerLast(x);
int n = q.size();
while (n-- > 1) {
q.offerLast(q.pollFirst());
}
}
/** Removes the element on top of the stack and returns that element. */
public int pop() {
return q.pollFirst();
}
/** Get the top element. */
public int top() {
return q.peekFirst();
}
/** Returns whether the stack is empty. */
public boolean empty() {
return q.isEmpty();
}
}
/**
* Your MyStack object will be instantiated and called as such:
* MyStack obj = new MyStack();
* obj.push(x);
* int param_2 = obj.pop();
* int param_3 = obj.top();
* boolean param_4 = obj.empty();
*/