给定一个矩阵 A
, 返回 A
的转置矩阵。
矩阵的转置是指将矩阵的主对角线翻转,交换矩阵的行索引与列索引。
示例 1:
输入:[[1,2,3],[4,5,6],[7,8,9]] 输出:[[1,4,7],[2,5,8],[3,6,9]]
示例 2:
输入:[[1,2,3],[4,5,6]] 输出:[[1,4],[2,5],[3,6]]
提示:
1 <= A.length <= 1000
1 <= A[0].length <= 1000
class Solution:
def transpose(self, matrix: List[List[int]]) -> List[List[int]]:
m, n = len(matrix), len(matrix[0])
res = [[0] * m for _ in range(n)]
for i in range(n):
for j in range(m):
res[i][j] = matrix[j][i]
return res
class Solution {
public int[][] transpose(int[][] matrix) {
int m = matrix.length, n = matrix[0].length;
int[][] res = new int[n][m];
for (int i = 0; i < n; ++i) {
for (int j = 0; j < m; ++j) {
res[i][j] = matrix[j][i];
}
}
return res;
}
}
/**
* @param {number[][]} matrix
* @return {number[][]}
*/
var transpose = function (matrix) {
const m = matrix.length,
n = matrix[0].length;
let res = [];
for (let i = 0; i < n; ++i) {
res[i] = [];
for (let j = 0; j < m; ++j) {
res[i][j] = matrix[j][i];
}
}
return res;
};