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Description

Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array.

Example 1:

Input: [3,0,1]

Output: 2

Example 2:

Input: [9,6,4,2,3,5,7,0,1]

Output: 8

Note:

Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?

Solutions

Python3

class Solution:
    def missingNumber(self, nums: List[int]) -> int:
        res = len(nums)
        for i, v in enumerate(nums):
            res ^= (i ^ v)
        return res

Java

  • XOR
class Solution {
    public int missingNumber(int[] nums) {
        int res = nums.length;
        for (int i = 0, n = res; i < n; ++i) {
            res ^= (i ^ nums[i]);
        }
        return res;
    }
}
  • Math
class Solution {
    public int missingNumber(int[] nums) {
        int res = nums.length;
        for (int i = 0, n = res; i < n; ++i) {
            res += (i - nums[i]);
        }
        return res;
    }
}

...