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Copy pathcopy-dlls.py
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copy-dlls.py
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#!/usr/bin/env python
#
# (C) Copyright 2024- ECMWF.
#
# This software is licensed under the terms of the Apache Licence Version 2.0
# which can be obtained at http://www.apache.org/licenses/LICENSE-2.0.
#
# In applying this licence, ECMWF does not waive the privileges and immunities
# granted to it by virtue of its status as an intergovernmental organisation nor
# does it submit to any jurisdiction.
#
import os
import shutil
import sys
from dlldiag.common import ModuleHeader
VCPKG1 = "C:/vcpkg/installed/{}-windows/bin/{}"
VCPKG2 = "C:/vcpkg/installed/{}-windows/debug/bin/{}"
def scan_module(module, depth, seen):
name = os.path.basename(module)
if name in seen:
return
if not os.path.exists(module):
return
print(" " * depth, module)
seen[name] = module
header = ModuleHeader(module)
cwd = os.path.dirname(module)
architecture = header.getArchitecture()
for dll in header.listAllImports():
# print("DEBUG", dll)
scan_module((cwd + "/" + dll), depth + 3, seen)
scan_module(VCPKG1.format(architecture, dll), depth + 3, seen)
scan_module(VCPKG2.format(architecture, dll), depth + 3, seen)
seen = {}
scan_module(sys.argv[1], 0, seen)
for k, v in seen.items():
target = sys.argv[2] + "/" + k
print("Copy", v, "to", target)
shutil.copyfile(v, target)