feat: update lc problems (#2208)

Co-authored-by: Doocs Bot <doocs-bot@outlook.com>

Author: acbin

solution/2700-2799/2746.Decremental String Concatenation/README_EN.md

@@ -68,15 +68,20 @@ It can be shown that the minimum possible length of str<sub>2</sub> is 6.
 
 ## Solutions
 
-**Solution 1: Case Discussion**
+**Solution 1: Memoization Search**
 
-We observe that the string 'AA' can only be followed by 'BB', and the string 'AB' can be placed at the beginning or end of the string. Therefore:
+We notice that when concatenating strings, the first and last characters of the string will affect the length of the concatenated string. Therefore, we design a function $dfs(i, a, b)$, which represents the minimum length of the concatenated string starting from the $i$-th string, and the first character of the previously concatenated string is $a$, and the last character is $b$.
 
--   If $x < y$, we can first alternately place 'BBAABBAA..BB', placing a total of $x$ 'AA' and $x+1$ 'BB', then place the remaining $z$ 'AB', with a total length of $(x \times 2 + z + 1) \times 2$;
--   If $x > y$, we can first alternately place 'AABBAABB..AA', placing a total of $y$ 'BB' and $y+1$ 'AA', then place the remaining $z$ 'AB', with a total length of $(y \times 2 + z + 1) \times 2$;
--   If $x = y$, we only need to alternately place 'AABB', placing a total of $x$ 'AA' and $y$ 'BB', then place the remaining $z$ 'AB', with a total length of $(x + y + z) \times 2$.
+The execution process of the function $dfs(i, a, b)$ is as follows:
 
-The time complexity is $O(1)$, and the space complexity is $O(1)$.
+-   If $i = n$, it means that all strings have been concatenated, return $0$;
+-   Otherwise, we consider concatenating the $i$-th string to the end or the beginning of the already concatenated string, and get the lengths $x$ and $y$ of the concatenated string, then $dfs(i, a, b) = \min(x, y) + |words[i]|$.
+
+To avoid repeated calculations, we use the method of memoization search. Specifically, we use a three-dimensional array $f$ to store all the return values of $dfs(i, a, b)$. When we need to calculate $dfs(i, a, b)$, if $f[i][a][b]$ has been calculated, we directly return $f[i][a][b]$; otherwise, we calculate the value of $dfs(i, a, b)$ according to the above recurrence relation, and store it in $f[i][a][b]$.
+
+In the main function, we directly return $|words[0]| + dfs(1, words[0][0], words[0][|words[0]| - 1])$.
+
+The time complexity is $O(n \times C^2)$, and the space complexity is $O(n \times C^2)$. Where $C$ represents the maximum length of the string.
 
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solution/3000-3099/3004.Maximum Subtree of the Same Color/README.md

@@ -15,7 +15,7 @@
 <p>Return <em>the size of such subtree with the <strong>maximum</strong> number of nodes possible.</em></p>
 
 <p>&nbsp;</p>
-<p><strong><img alt="" src="https://assets.leetcode.com/static_assets/others/20231216-134026.png" style="padding: 10px; background: rgb(255, 255, 255); border-radius: 0.5rem; width: 221px; height: 132px;" /></strong></p>
+<p><strong><img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/3000-3099/3004.Maximum%20Subtree%20of%20the%20Same%20Color/images/20231216-134026.png" style="padding: 10px; background: rgb(255, 255, 255); border-radius: 0.5rem; width: 221px; height: 132px;" /></strong></p>
 
 <p><strong class="example">Example 1:</strong></p>
 
@@ -33,7 +33,7 @@
 <strong>Explanation:</strong> The whole tree has the same color, and the subtree rooted at node 0 has the most number of nodes which is 4. Hence, we return 4.
 </pre>
 
-<p><strong><img alt="" src="https://assets.leetcode.com/static_assets/others/20231216-134017.png" style="padding: 10px; background: rgb(255, 255, 255); border-radius: 0.5rem; width: 221px; height: 221px;" /></strong></p>
+<p><strong><img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/3000-3099/3004.Maximum%20Subtree%20of%20the%20Same%20Color/images/20231216-134017.png" style="padding: 10px; background: rgb(255, 255, 255); border-radius: 0.5rem; width: 221px; height: 221px;" /></strong></p>
 
 <p><strong class="example">Example 3:</strong></p>
 

solution/3000-3099/3004.Maximum Subtree of the Same Color/README_EN.md

@@ -13,7 +13,7 @@
 <p>Return <em>the size of such subtree with the <strong>maximum</strong> number of nodes possible.</em></p>
 
 <p>&nbsp;</p>
-<p><strong><img alt="" src="https://assets.leetcode.com/static_assets/others/20231216-134026.png" style="padding: 10px; background: rgb(255, 255, 255); border-radius: 0.5rem; width: 221px; height: 132px;" /></strong></p>
+<p><strong><img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/3000-3099/3004.Maximum%20Subtree%20of%20the%20Same%20Color/images/20231216-134026.png" style="padding: 10px; background: rgb(255, 255, 255); border-radius: 0.5rem; width: 221px; height: 132px;" /></strong></p>
 
 <p><strong class="example">Example 1:</strong></p>
 
@@ -31,7 +31,7 @@
 <strong>Explanation:</strong> The whole tree has the same color, and the subtree rooted at node 0 has the most number of nodes which is 4. Hence, we return 4.
 </pre>
 
-<p><strong><img alt="" src="https://assets.leetcode.com/static_assets/others/20231216-134017.png" style="padding: 10px; background: rgb(255, 255, 255); border-radius: 0.5rem; width: 221px; height: 221px;" /></strong></p>
+<p><strong><img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/3000-3099/3004.Maximum%20Subtree%20of%20the%20Same%20Color/images/20231216-134017.png" style="padding: 10px; background: rgb(255, 255, 255); border-radius: 0.5rem; width: 221px; height: 221px;" /></strong></p>
 
 <p><strong class="example">Example 3:</strong></p>
 

solution/3000-3099/3004.Maximum Subtree of the Same Color/images/20231216-134017.png

@@ -256,8 +256,8 @@
 | 2989 | [班级表现](/solution/2900-2999/2989.Class%20Performance/README.md)                                                                                           | `数据库` | 中等 | 🔒   |
 | 2990 | [贷款类型](/solution/2900-2999/2990.Loan%20Types/README.md)                                                                                                  | `数据库` | 简单 | 🔒   |
 | 2991 | [最好的三家酒庄](/solution/2900-2999/2991.Top%20Three%20Wineries/README.md)                                                                                  | `数据库` | 困难 | 🔒   |
-| 2993 | [Friday Purchases I](/solution/2900-2999/2993.Friday%20Purchases%20I/README.md)                                                                              | `数据库` | 中等 | 🔒   |
-| 2994 | [Friday Purchases II](/solution/2900-2999/2994.Friday%20Purchases%20II/README.md)                                                                            | `数据库` | 困难 | 🔒   |
+| 2993 | [发生在周五的交易 I](/solution/2900-2999/2993.Friday%20Purchases%20I/README.md)                                                                              | `数据库` | 中等 | 🔒   |
+| 2994 | [发生在周五的交易 II](/solution/2900-2999/2994.Friday%20Purchases%20II/README.md)                                                                            | `数据库` | 困难 | 🔒   |
 | 2995 | [观众变主播](/solution/2900-2999/2995.Viewers%20Turned%20Streamers/README.md)                                                                                | `数据库` | 困难 | 🔒   |
 
 ## 版权

solution/3000-3099/3004.Maximum Subtree of the Same Color/images/20231216-134026.png

@@ -3003,8 +3003,8 @@
 |  2990  |  [贷款类型](/solution/2900-2999/2990.Loan%20Types/README.md)  |  `数据库`  |  简单  |  🔒  |
 |  2991  |  [最好的三家酒庄](/solution/2900-2999/2991.Top%20Three%20Wineries/README.md)  |  `数据库`  |  困难  |  🔒  |
 |  2992  |  [自整除排列的数量](/solution/2900-2999/2992.Number%20of%20Self-Divisible%20Permutations/README.md)  |  `位运算`,`递归`,`数组`,`动态规划`,`状态压缩`  |  中等  |  🔒  |
-|  2993  |  [Friday Purchases I](/solution/2900-2999/2993.Friday%20Purchases%20I/README.md)  |  `数据库`  |  中等  |  🔒  |
-|  2994  |  [Friday Purchases II](/solution/2900-2999/2994.Friday%20Purchases%20II/README.md)  |  `数据库`  |  困难  |  🔒  |
+|  2993  |  [发生在周五的交易 I](/solution/2900-2999/2993.Friday%20Purchases%20I/README.md)  |  `数据库`  |  中等  |  🔒  |
+|  2994  |  [发生在周五的交易 II](/solution/2900-2999/2994.Friday%20Purchases%20II/README.md)  |  `数据库`  |  困难  |  🔒  |
 |  2995  |  [观众变主播](/solution/2900-2999/2995.Viewers%20Turned%20Streamers/README.md)  |  `数据库`  |  困难  |  🔒  |
 |  2996  |  [大于等于顺序前缀和的最小缺失整数](/solution/2900-2999/2996.Smallest%20Missing%20Integer%20Greater%20Than%20Sequential%20Prefix%20Sum/README.md)  |  `数组`,`哈希表`,`排序`  |  简单  |  第 121 场双周赛  |
 |  2997  |  [使数组异或和等于 K 的最少操作次数](/solution/2900-2999/2997.Minimum%20Number%20of%20Operations%20to%20Make%20Array%20XOR%20Equal%20to%20K/README.md)  |  `位运算`,`数组`  |  中等  |  第 121 场双周赛  |
@@ -3014,7 +3014,7 @@
 |  3001  |  [捕获黑皇后需要的最少移动次数](/solution/3000-3099/3001.Minimum%20Moves%20to%20Capture%20The%20Queen/README.md)  |  `数组`,`枚举`  |  中等  |  第 379 场周赛  |
 |  3002  |  [移除后集合的最多元素数](/solution/3000-3099/3002.Maximum%20Size%20of%20a%20Set%20After%20Removals/README.md)  |  `贪心`,`数组`,`哈希表`  |  中等  |  第 379 场周赛  |
 |  3003  |  [执行操作后的最大分割数量](/solution/3000-3099/3003.Maximize%20the%20Number%20of%20Partitions%20After%20Operations/README.md)  |  `位运算`,`字符串`,`动态规划`,`状态压缩`  |  困难  |  第 379 场周赛  |
-|  3004  |  [Maximum Subtree of the Same Color](/solution/3000-3099/3004.Maximum%20Subtree%20of%20the%20Same%20Color/README.md)  |    |  中等  |  🔒  |
+|  3004  |  [相同颜色的最大子树](/solution/3000-3099/3004.Maximum%20Subtree%20of%20the%20Same%20Color/README.md)  |    |  中等  |  🔒  |
 
 ## 版权
 

solution/DATABASE_README.md

@@ -246,6 +246,6 @@
     -   [2989.班级表现](/database-solution/2900-2999/2989.Class%20Performance/README.md)
     -   [2990.贷款类型](/database-solution/2900-2999/2990.Loan%20Types/README.md)
     -   [2991.最好的三家酒庄](/database-solution/2900-2999/2991.Top%20Three%20Wineries/README.md)
-    -   [2993.Friday Purchases I](/database-solution/2900-2999/2993.Friday%20Purchases%20I/README.md)
-    -   [2994.Friday Purchases II](/database-solution/2900-2999/2994.Friday%20Purchases%20II/README.md)
+    -   [2993.发生在周五的交易 I](/database-solution/2900-2999/2993.Friday%20Purchases%20I/README.md)
+    -   [2994.发生在周五的交易 II](/database-solution/2900-2999/2994.Friday%20Purchases%20II/README.md)
     -   [2995.观众变主播](/database-solution/2900-2999/2995.Viewers%20Turned%20Streamers/README.md)

solution/README.md

@@ -3050,8 +3050,8 @@
   - [2990.贷款类型](/solution/2900-2999/2990.Loan%20Types/README.md)
   - [2991.最好的三家酒庄](/solution/2900-2999/2991.Top%20Three%20Wineries/README.md)
   - [2992.自整除排列的数量](/solution/2900-2999/2992.Number%20of%20Self-Divisible%20Permutations/README.md)
-  - [2993.Friday Purchases I](/solution/2900-2999/2993.Friday%20Purchases%20I/README.md)
-  - [2994.Friday Purchases II](/solution/2900-2999/2994.Friday%20Purchases%20II/README.md)
+  - [2993.发生在周五的交易 I](/solution/2900-2999/2993.Friday%20Purchases%20I/README.md)
+  - [2994.发生在周五的交易 II](/solution/2900-2999/2994.Friday%20Purchases%20II/README.md)
   - [2995.观众变主播](/solution/2900-2999/2995.Viewers%20Turned%20Streamers/README.md)
   - [2996.大于等于顺序前缀和的最小缺失整数](/solution/2900-2999/2996.Smallest%20Missing%20Integer%20Greater%20Than%20Sequential%20Prefix%20Sum/README.md)
   - [2997.使数组异或和等于 K 的最少操作次数](/solution/2900-2999/2997.Minimum%20Number%20of%20Operations%20to%20Make%20Array%20XOR%20Equal%20to%20K/README.md)
@@ -3063,4 +3063,4 @@
   - [3001.捕获黑皇后需要的最少移动次数](/solution/3000-3099/3001.Minimum%20Moves%20to%20Capture%20The%20Queen/README.md)
   - [3002.移除后集合的最多元素数](/solution/3000-3099/3002.Maximum%20Size%20of%20a%20Set%20After%20Removals/README.md)
   - [3003.执行操作后的最大分割数量](/solution/3000-3099/3003.Maximize%20the%20Number%20of%20Partitions%20After%20Operations/README.md)
-  - [3004.Maximum Subtree of the Same Color](/solution/3000-3099/3004.Maximum%20Subtree%20of%20the%20Same%20Color/README.md)
+  - [3004.相同颜色的最大子树](/solution/3000-3099/3004.Maximum%20Subtree%20of%20the%20Same%20Color/README.md)