feat: add sql solutions to lc problems: No.1113,1126 (#1200)

* No.1113.Reported Posts
* No.1126.Active Businesses

Author: yanglbme

Diff for: solution/1100-1199/1113.Reported Posts/README.md

@@ -67,17 +67,10 @@ Result table:
 
 ```sql
 # Write your MySQL query statement below
-SELECT
-	extra report_reason,
-	count(
-	DISTINCT ( post_id )) report_count
-FROM
-	Actions
-WHERE
-	action_date = '2019-07-04'
-	AND action = 'report'
-GROUP BY
-	extra
+SELECT extra AS report_reason, count(DISTINCT post_id) AS report_count
+FROM Actions
+WHERE action_date = '2019-07-04' AND action = 'report'
+GROUP BY 1;
 ```
 
 <!-- tabs:end -->

Diff for: solution/1100-1199/1113.Reported Posts/README_EN.md

@@ -71,17 +71,10 @@ Actions table:
 
 ```sql
 # Write your MySQL query statement below
-SELECT
-	extra report_reason,
-	count(
-	DISTINCT ( post_id )) report_count
-FROM
-	Actions
-WHERE
-	action_date = '2019-07-04'
-	AND action = 'report'
-GROUP BY
-	extra
+SELECT extra AS report_reason, count(DISTINCT post_id) AS report_count
+FROM Actions
+WHERE action_date = '2019-07-04' AND action = 'report'
+GROUP BY 1;
 ```
 
 <!-- tabs:end -->

Diff for: solution/1100-1199/1113.Reported Posts/Solution.sql

@@ -1,7 +1,5 @@
 # Write your MySQL query statement below
-SELECT
-    extra AS report_reason,
-    count(DISTINCT post_id) AS report_count
+SELECT extra AS report_reason, count(DISTINCT post_id) AS report_count
 FROM Actions
 WHERE action_date = '2019-07-04' AND action = 'report'
-GROUP BY extra;
+GROUP BY 1;

Diff for: solution/1100-1199/1126.Active Businesses/README.md

@@ -77,4 +77,20 @@ GROUP BY business_id
 HAVING COUNT(1) > 1;
 ```
 
+```sql
+# Write your MySQL query statement below
+WITH
+    T AS (
+        SELECT
+            business_id,
+            occurences > avg(occurences) OVER (PARTITION BY event_type) AS mark
+        FROM Events
+    )
+SELECT business_id
+FROM T
+WHERE mark = 1
+GROUP BY 1
+HAVING count(1) > 1;
+```
+
 <!-- tabs:end -->

Diff for: solution/1100-1199/1126.Active Businesses/README_EN.md

@@ -85,4 +85,20 @@ GROUP BY business_id
 HAVING COUNT(1) > 1;
 ```
 
+```sql
+# Write your MySQL query statement below
+WITH
+    T AS (
+        SELECT
+            business_id,
+            occurences > avg(occurences) OVER (PARTITION BY event_type) AS mark
+        FROM Events
+    )
+SELECT business_id
+FROM T
+WHERE mark = 1
+GROUP BY 1
+HAVING count(1) > 1;
+```
+
 <!-- tabs:end -->

Diff for: solution/1100-1199/1126.Active Businesses/Solution.sql

@@ -1,15 +1,13 @@
 # Write your MySQL query statement below
-SELECT business_id
-FROM
-    EVENTS AS t1
-    JOIN (
+WITH
+    T AS (
         SELECT
-            event_type,
-            AVG(occurences) AS occurences
-        FROM EVENTS
-        GROUP BY event_type
-    ) AS t2
-        ON t1.event_type = t2.event_type
-WHERE t1.occurences > t2.occurences
-GROUP BY business_id
-HAVING COUNT(1) > 1;
+            business_id,
+            occurences > avg(occurences) OVER (PARTITION BY event_type) AS mark
+        FROM Events
+    )
+SELECT business_id
+FROM T
+WHERE mark = 1
+GROUP BY 1
+HAVING count(1) > 1;