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solution/0100-0199/0160.Intersection of Two Linked Lists/README.md

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<pre>
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<strong>输入:</strong>intersectVal = 0, listA = [2,6,4], listB = [1,5], skipA = 3, skipB = 2
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<strong>输出:</strong>null
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<strong>输出:</strong>No intersection
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<strong>解释:</strong>从各自的表头开始算起,链表 A 为 [2,6,4],链表 B 为 [1,5]。
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由于这两个链表不相交,所以 intersectVal 必须为 0,而 skipA 和 skipB 可以是任意值。
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这两个链表不相交,因此返回 null 。

solution/0100-0199/0160.Intersection of Two Linked Lists/README_EN.md

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<li>The number of nodes of <code>listB</code> is in the <code>n</code>.</li>
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<li><code>1 &lt;= m, n &lt;= 3 * 10<sup>4</sup></code></li>
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<li><code>1 &lt;= Node.val &lt;= 10<sup>5</sup></code></li>
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<li><code>0 &lt;= skipA &lt;&nbsp;m</code></li>
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<li><code>0 &lt;= skipB &lt;&nbsp;n</code></li>
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<li><code>0 &lt;= skipA &lt;= m</code></li>
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<li><code>0 &lt;= skipB &lt;= n</code></li>
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<li><code>intersectVal</code> is <code>0</code> if <code>listA</code> and <code>listB</code> do not intersect.</li>
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<li><code>intersectVal == listA[skipA] == listB[skipB]</code> if <code>listA</code> and <code>listB</code> intersect.</li>
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</ul>

solution/0100-0199/0191.Number of 1 Bits/README.md

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<!-- description:start -->
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<p>编写一个函数,获取一个正整数的二进制形式并返回其二进制表达式中 <span data-keyword="set-bit">设置位</span> 的个数(也被称为<a href="https://baike.baidu.com/item/%E6%B1%89%E6%98%8E%E9%87%8D%E9%87%8F" target="_blank">汉明重量</a>)。</p>
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<p>给定一个正整数 <code>n</code>,编写一个函数,获取一个正整数的二进制形式并返回其二进制表达式中 <span data-keyword="set-bit">设置位</span> 的个数(也被称为<a href="https://baike.baidu.com/item/%E6%B1%89%E6%98%8E%E9%87%8D%E9%87%8F" target="_blank">汉明重量</a>)。</p>
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<p>&nbsp;</p>
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solution/1800-1899/1808.Maximize Number of Nice Divisors/README.md

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tags:
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- 递归
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- 数学
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- 数论
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---
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<!-- problem:start -->

solution/1800-1899/1808.Maximize Number of Nice Divisors/README_EN.md

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tags:
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- Recursion
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- Math
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- Number Theory
1011
---
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1213
<!-- problem:start -->

solution/3000-3099/3043.Find the Length of the Longest Common Prefix/README.md

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<p>正整数的 <strong>前缀 </strong>是其 <strong>最左边 </strong>的一位或多位数字组成的整数。例如,<code>123</code> 是整数 <code>12345</code> 的前缀,而 <code>234</code><strong> 不是 </strong>。</p>
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<p>设若整数 <code>c</code> 是整数 <code>a</code> 和 <code>b</code> 的<strong> 公共前缀 </strong>,那么 <code>c</code> 需要同时是 <code>a</code> 和 <code>b</code> 的前缀。例如,<code>5655359</code> 和 <code>56554</code> 有公共前缀 <code>565</code> ,而 <code>1223</code> 和 <code>43456</code><strong> 没有 </strong>公共前缀。</p>
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<p>设若整数 <code>c</code> 是整数 <code>a</code> 和 <code>b</code> 的<strong> 公共前缀 </strong>,那么 <code>c</code> 需要同时是 <code>a</code> 和 <code>b</code> 的前缀。例如,<code>5655359</code> 和 <code>56554</code> 有公共前缀 <code>565</code>&nbsp;和 <code>5655</code>,而 <code>1223</code> 和 <code>43456</code><strong> 没有 </strong>公共前缀。</p>
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<p>你需要找出属于 <code>arr1</code> 的整数 <code>x</code> 和属于 <code>arr2</code> 的整数 <code>y</code> 组成的所有数对 <code>(x, y)</code> 之中最长的公共前缀的长度。</p>
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solution/3000-3099/3043.Find the Length of the Longest Common Prefix/README_EN.md

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<p>A <strong>prefix</strong> of a positive integer is an integer formed by one or more of its digits, starting from its <strong>leftmost</strong> digit. For example, <code>123</code> is a prefix of the integer <code>12345</code>, while <code>234</code> is <strong>not</strong>.</p>
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<p>A <strong>common prefix</strong> of two integers <code>a</code> and <code>b</code> is an integer <code>c</code>, such that <code>c</code> is a prefix of both <code>a</code> and <code>b</code>. For example, <code>5655359</code> and <code>56554</code> have a common prefix <code>565</code> while <code>1223</code> and <code>43456</code> <strong>do not</strong> have a common prefix.</p>
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<p>A <strong>common prefix</strong> of two integers <code>a</code> and <code>b</code> is an integer <code>c</code>, such that <code>c</code> is a prefix of both <code>a</code> and <code>b</code>. For example, <code>5655359</code> and <code>56554</code> have common prefixes <code>565</code> and <code>5655</code> while <code>1223</code> and <code>43456</code> <strong>do not</strong> have a common prefix.</p>
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<p>You need to find the length of the <strong>longest common prefix</strong> between all pairs of integers <code>(x, y)</code> such that <code>x</code> belongs to <code>arr1</code> and <code>y</code> belongs to <code>arr2</code>.</p>
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solution/3300-3399/3323.Minimize Connected Groups by Inserting Interval/README.md

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comments: true
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difficulty: 中等
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3323.Minimize%20Connected%20Groups%20by%20Inserting%20Interval/README.md
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tags:
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- 数组
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- 二分查找
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- 排序
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---
610

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<!-- problem:start -->

solution/3300-3399/3323.Minimize Connected Groups by Inserting Interval/README_EN.md

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comments: true
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difficulty: Medium
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3323.Minimize%20Connected%20Groups%20by%20Inserting%20Interval/README_EN.md
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tags:
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- Array
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- Binary Search
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- Sorting
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---
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<!-- problem:start -->

solution/3300-3399/3324.Find the Sequence of Strings Appeared on the Screen/README.md

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comments: true
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difficulty: 中等
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3324.Find%20the%20Sequence%20of%20Strings%20Appeared%20on%20the%20Screen/README.md
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tags:
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- 字符串
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- 模拟
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---
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<!-- problem:start -->

solution/3300-3399/3324.Find the Sequence of Strings Appeared on the Screen/README_EN.md

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comments: true
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difficulty: Medium
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3324.Find%20the%20Sequence%20of%20Strings%20Appeared%20on%20the%20Screen/README_EN.md
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tags:
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- String
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- Simulation
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---
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<!-- problem:start -->

solution/3300-3399/3325.Count Substrings With K-Frequency Characters I/README.md

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comments: true
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difficulty: 中等
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3325.Count%20Substrings%20With%20K-Frequency%20Characters%20I/README.md
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tags:
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- 哈希表
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- 字符串
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- 滑动窗口
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---
610

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<!-- problem:start -->

solution/3300-3399/3325.Count Substrings With K-Frequency Characters I/README_EN.md

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comments: true
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difficulty: Medium
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3325.Count%20Substrings%20With%20K-Frequency%20Characters%20I/README_EN.md
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tags:
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- Hash Table
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- String
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- Sliding Window
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---
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<!-- problem:start -->
@@ -14,9 +18,7 @@ edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3325.Co
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<!-- description:start -->
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<p>Given a string <code>s</code> and an integer <code>k</code>, return the total number of substrings of <code>s</code> where <strong>at least one</strong> character appears <strong>at least</strong> <code>k</code> times.</p>
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<p>A <strong>substring</strong> is a contiguous <b>non-empty</b> sequence of characters within a string.</p>
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<p>Given a string <code>s</code> and an integer <code>k</code>, return the total number of <span data-keyword="substring-nonempty">substrings</span> of <code>s</code> where <strong>at least one</strong> character appears <strong>at least</strong> <code>k</code> times.</p>
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<p>&nbsp;</p>
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<p><strong class="example">Example 1:</strong></p>

solution/3300-3399/3326.Minimum Division Operations to Make Array Non Decreasing/README.md

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comments: true
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difficulty: 中等
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3326.Minimum%20Division%20Operations%20to%20Make%20Array%20Non%20Decreasing/README.md
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tags:
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- 贪心
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- 数组
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- 数学
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- 数论
510
---
611

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<!-- problem:start -->

solution/3300-3399/3326.Minimum Division Operations to Make Array Non Decreasing/README_EN.md

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comments: true
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difficulty: Medium
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3326.Minimum%20Division%20Operations%20to%20Make%20Array%20Non%20Decreasing/README_EN.md
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tags:
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- Greedy
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- Array
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- Math
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- Number Theory
510
---
611

712
<!-- problem:start -->

solution/3300-3399/3327.Check if DFS Strings Are Palindromes/README.md

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comments: true
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difficulty: 困难
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3327.Check%20if%20DFS%20Strings%20Are%20Palindromes/README.md
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tags:
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-
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- 深度优先搜索
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- 数组
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- 哈希表
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- 字符串
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- 哈希函数
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---
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<!-- problem:start -->
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}
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dfsStr.append(s[i]);
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int r = dfsStr.length();
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pos[i] = new int[]{l, r};
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pos[i] = new int[] {l, r};
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}
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}
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```

solution/3300-3399/3327.Check if DFS Strings Are Palindromes/README_EN.md

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comments: true
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difficulty: Hard
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3327.Check%20if%20DFS%20Strings%20Are%20Palindromes/README_EN.md
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tags:
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- Tree
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- Depth-First Search
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- Array
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- Hash Table
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- String
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- Hash Function
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<!-- problem:start -->
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<ul>
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<li>Empty the string <code>dfsStr</code> and call <code>dfs(i)</code>.</li>
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<li>If the resulting string <code>dfsStr</code> is a <strong>palindrome</strong>, then set <code>answer[i]</code> to <code>true</code>. Otherwise, set <code>answer[i]</code> to <code>false</code>.</li>
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<li>If the resulting string <code>dfsStr</code> is a <span data-keyword="palindrome-string">palindrome</span>, then set <code>answer[i]</code> to <code>true</code>. Otherwise, set <code>answer[i]</code> to <code>false</code>.</li>
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</ul>
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<p>Return the array <code>answer</code>.</p>
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<p>A <strong>palindrome</strong> is a string that reads the same forward and backward.</p>
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<p>&nbsp;</p>
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<p><strong class="example">Example 1:</strong></p>
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<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/3300-3399/3327.Check%20if%20DFS%20Strings%20Are%20Palindromes/images/tree1drawio.png" style="width: 240px; height: 256px;" />
@@ -210,7 +215,7 @@ class Solution {
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dfsStr.append(s[i]);
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pos[i] = new int[]{l, r};
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pos[i] = new int[] {l, r};
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}
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}
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```

solution/3300-3399/3327.Check if DFS Strings Are Palindromes/Solution.java

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dfsStr.append(s[i]);
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pos[i] = new int[]{l, r};
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pos[i] = new int[] {l, r};
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}
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}

solution/3300-3399/3328.Find Cities in Each State II/README.md

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2020

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<pre>
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+-------------+---------+
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| Column Name | Type |
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| Column Name | Type |
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+-------------+---------+
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| state | varchar |
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| city | varchar |

solution/3300-3399/3328.Find Cities in Each State II/README_EN.md

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2020

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<pre>
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+-------------+---------+
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| Column Name | Type |
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| Column Name | Type |
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+-------------+---------+
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| state | varchar |
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| city | varchar |

solution/CONTEST_README.md

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## 往期竞赛
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#### 第 420 场周赛(2024-10-20 10:30, 90 分钟) 参赛人数 2921
29+
#### 第 420 场周赛(2024-10-20 10:30, 90 分钟) 参赛人数 2995
3030

3131
- [3324. 出现在屏幕上的字符串序列](/solution/3300-3399/3324.Find%20the%20Sequence%20of%20Strings%20Appeared%20on%20the%20Screen/README.md)
3232
- [3325. 字符至少出现 K 次的子字符串 I](/solution/3300-3399/3325.Count%20Substrings%20With%20K-Frequency%20Characters%20I/README.md)

solution/DATABASE_README.md

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@@ -298,7 +298,7 @@
298298
| 3293 | [计算产品最终价格](/solution/3200-3299/3293.Calculate%20Product%20Final%20Price/README.md) | `数据库` | 中等 | 🔒 |
299299
| 3308 | [Find Top Performing Driver](/solution/3300-3399/3308.Find%20Top%20Performing%20Driver/README.md) | `数据库` | 中等 | 🔒 |
300300
| 3322 | [英超积分榜排名 III](/solution/3300-3399/3322.Premier%20League%20Table%20Ranking%20III/README.md) | `数据库` | 中等 | 🔒 |
301-
| 3328 | [Find Cities in Each State II](/solution/3300-3399/3328.Find%20Cities%20in%20Each%20State%20II/README.md) | | 中等 | 🔒 |
301+
| 3328 | [Find Cities in Each State II](/solution/3300-3399/3328.Find%20Cities%20in%20Each%20State%20II/README.md) | `数据库` | 中等 | 🔒 |
302302

303303
## 版权
304304

solution/DATABASE_README_EN.md

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@@ -296,7 +296,7 @@ Press <kbd>Control</kbd> + <kbd>F</kbd>(or <kbd>Command</kbd> + <kbd>F</kbd> on
296296
| 3293 | [Calculate Product Final Price](/solution/3200-3299/3293.Calculate%20Product%20Final%20Price/README_EN.md) | `Database` | Medium | 🔒 |
297297
| 3308 | [Find Top Performing Driver](/solution/3300-3399/3308.Find%20Top%20Performing%20Driver/README_EN.md) | `Database` | Medium | 🔒 |
298298
| 3322 | [Premier League Table Ranking III](/solution/3300-3399/3322.Premier%20League%20Table%20Ranking%20III/README_EN.md) | `Database` | Medium | 🔒 |
299-
| 3328 | [Find Cities in Each State II](/solution/3300-3399/3328.Find%20Cities%20in%20Each%20State%20II/README_EN.md) | | Medium | 🔒 |
299+
| 3328 | [Find Cities in Each State II](/solution/3300-3399/3328.Find%20Cities%20in%20Each%20State%20II/README_EN.md) | `Database` | Medium | 🔒 |
300300

301301
## Copyright
302302

solution/README.md

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@@ -1818,7 +1818,7 @@
18181818
| 1805 | [字符串中不同整数的数目](/solution/1800-1899/1805.Number%20of%20Different%20Integers%20in%20a%20String/README.md) | `哈希表`,`字符串` | 简单 | 第 234 场周赛 |
18191819
| 1806 | [还原排列的最少操作步数](/solution/1800-1899/1806.Minimum%20Number%20of%20Operations%20to%20Reinitialize%20a%20Permutation/README.md) | `数组`,`数学`,`模拟` | 中等 | 第 234 场周赛 |
18201820
| 1807 | [替换字符串中的括号内容](/solution/1800-1899/1807.Evaluate%20the%20Bracket%20Pairs%20of%20a%20String/README.md) | `数组`,`哈希表`,`字符串` | 中等 | 第 234 场周赛 |
1821-
| 1808 | [好因子的最大数目](/solution/1800-1899/1808.Maximize%20Number%20of%20Nice%20Divisors/README.md) | `递归`,`数学` | 困难 | 第 234 场周赛 |
1821+
| 1808 | [好因子的最大数目](/solution/1800-1899/1808.Maximize%20Number%20of%20Nice%20Divisors/README.md) | `递归`,`数学`,`数论` | 困难 | 第 234 场周赛 |
18221822
| 1809 | [没有广告的剧集](/solution/1800-1899/1809.Ad-Free%20Sessions/README.md) | `数据库` | 简单 | 🔒 |
18231823
| 1810 | [隐藏网格下的最小消耗路径](/solution/1800-1899/1810.Minimum%20Path%20Cost%20in%20a%20Hidden%20Grid/README.md) | `深度优先搜索`,`广度优先搜索`,`图`,`交互`,`堆(优先队列)` | 中等 | 🔒 |
18241824
| 1811 | [寻找面试候选人](/solution/1800-1899/1811.Find%20Interview%20Candidates/README.md) | `数据库` | 中等 | 🔒 |
@@ -3333,12 +3333,12 @@
33333333
| 3320 | [统计能获胜的出招序列数](/solution/3300-3399/3320.Count%20The%20Number%20of%20Winning%20Sequences/README.md) | `字符串`,`动态规划` | 困难 | 第 419 场周赛 |
33343334
| 3321 | [计算子数组的 x-sum II](/solution/3300-3399/3321.Find%20X-Sum%20of%20All%20K-Long%20Subarrays%20II/README.md) | `数组`,`哈希表`,`滑动窗口`,`堆(优先队列)` | 困难 | 第 419 场周赛 |
33353335
| 3322 | [英超积分榜排名 III](/solution/3300-3399/3322.Premier%20League%20Table%20Ranking%20III/README.md) | `数据库` | 中等 | 🔒 |
3336-
| 3323 | [通过插入区间最小化连通组](/solution/3300-3399/3323.Minimize%20Connected%20Groups%20by%20Inserting%20Interval/README.md) | | 中等 | 🔒 |
3337-
| 3324 | [出现在屏幕上的字符串序列](/solution/3300-3399/3324.Find%20the%20Sequence%20of%20Strings%20Appeared%20on%20the%20Screen/README.md) | | 中等 | 第 420 场周赛 |
3338-
| 3325 | [字符至少出现 K 次的子字符串 I](/solution/3300-3399/3325.Count%20Substrings%20With%20K-Frequency%20Characters%20I/README.md) | | 中等 | 第 420 场周赛 |
3339-
| 3326 | [使数组非递减的最少除法操作次数](/solution/3300-3399/3326.Minimum%20Division%20Operations%20to%20Make%20Array%20Non%20Decreasing/README.md) | | 中等 | 第 420 场周赛 |
3340-
| 3327 | [判断 DFS 字符串是否是回文串](/solution/3300-3399/3327.Check%20if%20DFS%20Strings%20Are%20Palindromes/README.md) | | 困难 | 第 420 场周赛 |
3341-
| 3328 | [Find Cities in Each State II](/solution/3300-3399/3328.Find%20Cities%20in%20Each%20State%20II/README.md) | | 中等 | 🔒 |
3336+
| 3323 | [通过插入区间最小化连通组](/solution/3300-3399/3323.Minimize%20Connected%20Groups%20by%20Inserting%20Interval/README.md) | `数组`,`二分查找`,`排序` | 中等 | 🔒 |
3337+
| 3324 | [出现在屏幕上的字符串序列](/solution/3300-3399/3324.Find%20the%20Sequence%20of%20Strings%20Appeared%20on%20the%20Screen/README.md) | `字符串`,`模拟` | 中等 | 第 420 场周赛 |
3338+
| 3325 | [字符至少出现 K 次的子字符串 I](/solution/3300-3399/3325.Count%20Substrings%20With%20K-Frequency%20Characters%20I/README.md) | `哈希表`,`字符串`,`滑动窗口` | 中等 | 第 420 场周赛 |
3339+
| 3326 | [使数组非递减的最少除法操作次数](/solution/3300-3399/3326.Minimum%20Division%20Operations%20to%20Make%20Array%20Non%20Decreasing/README.md) | `贪心`,`数组`,`数学`,`数论` | 中等 | 第 420 场周赛 |
3340+
| 3327 | [判断 DFS 字符串是否是回文串](/solution/3300-3399/3327.Check%20if%20DFS%20Strings%20Are%20Palindromes/README.md) | `树`,`深度优先搜索`,`数组`,`哈希表`,`字符串`,`哈希函数` | 困难 | 第 420 场周赛 |
3341+
| 3328 | [Find Cities in Each State II](/solution/3300-3399/3328.Find%20Cities%20in%20Each%20State%20II/README.md) | `数据库` | 中等 | 🔒 |
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