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diff --git a/‎lcof/面试题24. 反转链表/README.md
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diff --git a/‎lcof/面试题24. 反转链表/Solution.java
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diff --git a/‎lcof/面试题25. 合并两个排序的链表/README.md
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diff --git a/‎lcof/面试题35. 复杂链表的复制/README.md
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diff --git a/‎lcof/面试题36. 二叉搜索树与双向链表/README.md
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@@ -9,16 +9,16 @@
   <meta name="viewport" content="width=device-width, user-scalable=no, initial-scale=1.0, maximum-scale=1.0, minimum-scale=1.0">
   <link rel="stylesheet" href="//unpkg.com/docsify/lib/themes/vue.css">
   <link rel="stylesheet" href="//unpkg.com/docsify-dark-mode@0.6.1/dist/style.css" />
-  <link rel="icon" type="image/png" sizes="32x32" href="img/favicon-32x32.png">
-  <link rel="icon" type="image/png" sizes="16x16" href="img/favicon-16x16.png">
+  <link rel="icon" type="image/png" sizes="32x32" href="images/favicon-32x32.png">
+  <link rel="icon" type="image/png" sizes="16x16" href="images/favicon-16x16.png">
 </head>
 
 <body>
-  <div id="app">本系列知识由 Doocs 开源社区原创发布</div>
+  <div id="app">本系列知识由 Doocs 技术社区原创发布</div>
   <script>
     window.$docsify = {
       name: 'leetcode',
-      logo: '/img/doocs-leetcode.png',
+      logo: '/images/doocs-leetcode.png',
       search: [
         '/','/solution/','/lcof/','lcci/'
       ],
 
@@ -8,17 +8,14 @@
  */
 class Solution {
     public ListNode reverseList(ListNode head) {
-        if (head == null) {
-            return head;
-        }
-        ListNode dummy = new ListNode(0);
+        ListNode pre = null;
         ListNode p = head;
         while (p != null) {
             ListNode q = p.next;
-            p.next = dummy.next;
-            dummy.next = p;
+            p.next = pre;
+            pre = p;
             p = q;
         }
-        return dummy.next;
+        return pre;
     }
 }
@@ -6,13 +6,10 @@
 
 class Solution:
     def reverseList(self, head: ListNode) -> ListNode:
-        if not head:
-            return head
-        dummy = ListNode(0)
-        p = head
+        pre, p = None, head
         while p:
             q = p.next
-            p.next = dummy.next
-            dummy.next = p
+            p.next = pre
+            pre = p
             p = q
-        return dummy.next
+        return pre