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feat: update leetcode solutions: No.0081
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-14
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4 files changed

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‎solution/0000-0099/0081.Search in Rotated Sorted Array II/README.md

+39-2
Original file line numberDiff line numberDiff line change
@@ -33,22 +33,59 @@
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<!-- 这里可写通用的实现逻辑 -->
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二分查找。
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<!-- tabs:start -->
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### **Python3**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```python
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class Solution:
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def search(self, nums: List[int], target: int) -> bool:
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l, r = 0, len(nums) - 1
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while l <= r:
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mid = (l + r) >> 1
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if nums[mid] == target:
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return True
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if nums[mid] < nums[r] or nums[mid] < nums[l]:
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if target > nums[mid] and target <= nums[r]:
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l = mid + 1
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else:
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r = mid - 1
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elif nums[mid] > nums[l] or nums[mid] > nums[r]:
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if target < nums[mid] and target >= nums[l]:
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r = mid - 1
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else:
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l = mid + 1
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else:
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r -= 1
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return False
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```
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### **Java**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```java
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class Solution {
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public boolean search(int[] nums, int target) {
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int l = 0, r = nums.length - 1;
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while (l <= r) {
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int mid = (l + r) >>> 1;
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if (nums[mid] == target) return true;
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if (nums[mid] < nums[r] || nums[mid] < nums[l]) {
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if (target > nums[mid] && target <= nums[r]) l = mid + 1;
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else r = mid - 1;
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} else if (nums[mid] > nums[l] || nums[mid] > nums[r]) {
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if (target < nums[mid] && target >= nums[l]) r = mid - 1;
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else l = mid + 1;
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} else r--;
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}
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return false;
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}
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}
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```
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### **C++**

‎solution/0000-0099/0081.Search in Rotated Sorted Array II/README_EN.md

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Original file line numberDiff line numberDiff line change
@@ -42,13 +42,48 @@
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### **Python3**
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```python
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class Solution:
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def search(self, nums: List[int], target: int) -> bool:
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l, r = 0, len(nums) - 1
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while l <= r:
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mid = (l + r) >> 1
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if nums[mid] == target:
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return True
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if nums[mid] < nums[r] or nums[mid] < nums[l]:
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if target > nums[mid] and target <= nums[r]:
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l = mid + 1
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else:
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r = mid - 1
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elif nums[mid] > nums[l] or nums[mid] > nums[r]:
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if target < nums[mid] and target >= nums[l]:
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r = mid - 1
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else:
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l = mid + 1
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else:
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r -= 1
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return False
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```
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### **Java**
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```java
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class Solution {
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public boolean search(int[] nums, int target) {
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int l = 0, r = nums.length - 1;
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while (l <= r) {
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int mid = (l + r) >>> 1;
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if (nums[mid] == target) return true;
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if (nums[mid] < nums[r] || nums[mid] < nums[l]) {
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if (target > nums[mid] && target <= nums[r]) l = mid + 1;
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else r = mid - 1;
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} else if (nums[mid] > nums[l] || nums[mid] > nums[r]) {
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if (target < nums[mid] && target >= nums[l]) r = mid - 1;
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else l = mid + 1;
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} else r--;
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}
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return false;
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}
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}
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```
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### **C++**

‎solution/0000-0099/0081.Search in Rotated Sorted Array II/Solution.java

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Original file line numberDiff line numberDiff line change
@@ -1,16 +1,16 @@
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class Solution {
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public boolean search(int[] nums, int target) {
3-
int start = 0, end = nums.length - 1, mid;
4-
while(start <= end) {
5-
mid = (start + end) / 2;
3+
int l = 0, r = nums.length - 1;
4+
while (l <= r) {
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int mid = (l + r) >>> 1;
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if (nums[mid] == target) return true;
7-
if (nums[mid] < nums[end] || nums[mid] < nums[start]) {
8-
if (target > nums[mid] && target <= nums[end]) start = mid + 1;
9-
else end = mid - 1;
10-
} else if (nums[mid] > nums[start] || nums[mid] > nums[end]) {
11-
if (target < nums[mid] && target >= nums[start]) end = mid - 1;
12-
else start = mid + 1;
13-
} else end--;
7+
if (nums[mid] < nums[r] || nums[mid] < nums[l]) {
8+
if (target > nums[mid] && target <= nums[r]) l = mid + 1;
9+
else r = mid - 1;
10+
} else if (nums[mid] > nums[l] || nums[mid] > nums[r]) {
11+
if (target < nums[mid] && target >= nums[l]) r = mid - 1;
12+
else l = mid + 1;
13+
} else r--;
1414
}
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return false;
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}

‎solution/0000-0099/0081.Search in Rotated Sorted Array II/Solution.py

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Original file line numberDiff line numberDiff line change
@@ -0,0 +1,20 @@
1+
class Solution:
2+
def search(self, nums: List[int], target: int) -> bool:
3+
l, r = 0, len(nums) - 1
4+
while l <= r:
5+
mid = (l + r) >> 1
6+
if nums[mid] == target:
7+
return True
8+
if nums[mid] < nums[r] or nums[mid] < nums[l]:
9+
if target > nums[mid] and target <= nums[r]:
10+
l = mid + 1
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else:
12+
r = mid - 1
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elif nums[mid] > nums[l] or nums[mid] > nums[r]:
14+
if target < nums[mid] and target >= nums[l]:
15+
r = mid - 1
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else:
17+
l = mid + 1
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else:
19+
r -= 1
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return False

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