feat: add sql solution to lc problem: No.1767

No.1767.Find the Subtasks That Did Not Execute

Author: yanglbme

solution/1700-1799/1767.Find the Subtasks That Did Not Execute/README.md

@@ -86,14 +86,39 @@ Task 3 被分成了 4 subtasks (1, 2, 3, 4)。所有的subtask都被成功执行
 
 <!-- 这里可写通用的实现逻辑 -->
 
+**方法一：递归生成数据表**
+
 <!-- tabs:start -->
 
 ### **SQL**
 
 <!-- 这里可写当前语言的特殊实现逻辑 -->
 
 ```sql
-
+# Write your MySQL query statement below
+with recursive t(task_id, subtask_id) as (
+    select
+        task_id,
+        subtasks_count
+    from
+        Tasks
+    union
+    all
+    select
+        task_id,
+        subtask_id - 1
+    from
+        t
+    where
+        subtask_id >= 2
+)
+select
+    t.*
+from
+    t
+    left join Executed e using(task_id, subtask_id)
+where
+    e.subtask_id is null
 ```
 
 <!-- tabs:end -->

solution/1700-1799/1767.Find the Subtasks That Did Not Execute/README_EN.md

@@ -86,7 +86,30 @@ Task 3 was divided into 4 subtasks (1, 2, 3, 4). All of the subtasks were execut
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+with recursive t(task_id, subtask_id) as (
+    select
+        task_id,
+        subtasks_count
+    from
+        Tasks
+    union
+    all
+    select
+        task_id,
+        subtask_id - 1
+    from
+        t
+    where
+        subtask_id >= 2
+)
+select
+    t.*
+from
+    t
+    left join Executed e using(task_id, subtask_id)
+where
+    e.subtask_id is null
 ```
 
 <!-- tabs:end -->

solution/1700-1799/1767.Find the Subtasks That Did Not Execute/Solution.sql

@@ -0,0 +1,24 @@
+# Write your MySQL query statement below
+with recursive t(task_id, subtask_id) as (
+    select
+        task_id,
+        subtasks_count
+    from
+        Tasks
+    union
+    all
+    select
+        task_id,
+        subtask_id - 1
+    from
+        t
+    where
+        subtask_id >= 2
+)
+select
+    t.*
+from
+    t
+    left join Executed e using(task_id, subtask_id)
+where
+    e.subtask_id is null