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27 | 27 | <strong>输出:</strong> [[1,2,6], [1,3,5], [2,3,4]]
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28 | 28 | </pre>
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29 | 29 |
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30 |
| - |
31 | 30 | ## 解法
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32 | 31 |
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33 | 32 | <!-- 这里可写通用的实现逻辑 -->
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34 | 33 |
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| 34 | +DFS 回溯法。 |
| 35 | + |
35 | 36 | <!-- tabs:start -->
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36 | 37 |
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37 | 38 | ### **Python3**
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38 | 39 |
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39 | 40 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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40 | 41 |
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41 | 42 | ```python
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42 |
| - |
| 43 | +class Solution: |
| 44 | + def combinationSum3(self, k: int, n: int) -> List[List[int]]: |
| 45 | + def dfs(i, s, t): |
| 46 | + if i > 9 or s > n or len(t) > k: |
| 47 | + return |
| 48 | + if s == n and len(t) == k: |
| 49 | + ans.append(t[:]) |
| 50 | + return |
| 51 | + i += 1 |
| 52 | + t.append(i) |
| 53 | + dfs(i, s + i, t) |
| 54 | + t.pop() |
| 55 | + dfs(i, s, t) |
| 56 | + |
| 57 | + ans = [] |
| 58 | + dfs(0, 0, []) |
| 59 | + return ans |
43 | 60 | ```
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44 | 61 |
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45 | 62 | ### **Java**
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46 | 63 |
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47 | 64 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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48 | 65 |
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49 | 66 | ```java
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| 67 | +class Solution { |
| 68 | + private List<List<Integer>> ans; |
| 69 | + |
| 70 | + public List<List<Integer>> combinationSum3(int k, int n) { |
| 71 | + ans = new ArrayList<>(); |
| 72 | + dfs(0, n, k, new ArrayList<>()); |
| 73 | + return ans; |
| 74 | + } |
| 75 | + |
| 76 | + private void dfs(int i, int n, int k, List<Integer> t) { |
| 77 | + if (i > 9 || n < 0 || t.size() > k) { |
| 78 | + return; |
| 79 | + } |
| 80 | + if (n == 0 && t.size() == k) { |
| 81 | + ans.add(new ArrayList<>(t)); |
| 82 | + return; |
| 83 | + } |
| 84 | + ++i; |
| 85 | + t.add(i); |
| 86 | + dfs(i, n - i, k, t); |
| 87 | + t.remove(t.size() - 1); |
| 88 | + dfs(i, n, k, t); |
| 89 | + } |
| 90 | +} |
| 91 | +``` |
| 92 | + |
| 93 | +### **C++** |
| 94 | + |
| 95 | +```cpp |
| 96 | +class Solution { |
| 97 | +public: |
| 98 | + vector<vector<int>> ans; |
| 99 | + |
| 100 | + vector<vector<int>> combinationSum3(int k, int n) { |
| 101 | + vector<int> t; |
| 102 | + dfs(0, n, k, t); |
| 103 | + return ans; |
| 104 | + } |
| 105 | + |
| 106 | + void dfs(int i, int n, int k, vector<int>& t) { |
| 107 | + if (i > 9 || n < 0 || t.size() > k) return; |
| 108 | + if (n == 0 && t.size() == k) |
| 109 | + { |
| 110 | + ans.push_back(t); |
| 111 | + return; |
| 112 | + } |
| 113 | + ++i; |
| 114 | + t.push_back(i); |
| 115 | + dfs(i, n - i, k, t); |
| 116 | + t.pop_back(); |
| 117 | + dfs(i, n, k, t); |
| 118 | + } |
| 119 | +}; |
| 120 | +``` |
50 | 121 |
|
| 122 | +### **Go** |
| 123 | +
|
| 124 | +```go |
| 125 | +func combinationSum3(k int, n int) [][]int { |
| 126 | + var ans [][]int |
| 127 | + var t []int |
| 128 | + var dfs func(i, n int, t []int) |
| 129 | + dfs = func(i, n int, t []int) { |
| 130 | + if i > 9 || n < 0 || len(t) > k { |
| 131 | + return |
| 132 | + } |
| 133 | + if n == 0 && len(t) == k { |
| 134 | + cp := make([]int, len(t)) |
| 135 | + copy(cp, t) |
| 136 | + ans = append(ans, cp) |
| 137 | + return |
| 138 | + } |
| 139 | + i++ |
| 140 | + t = append(t, i) |
| 141 | + dfs(i, n-i, t) |
| 142 | + t = t[:len(t)-1] |
| 143 | + dfs(i, n, t) |
| 144 | + } |
| 145 | +
|
| 146 | + dfs(0, n, t) |
| 147 | + return ans |
| 148 | +} |
51 | 149 | ```
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52 | 150 |
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53 | 151 | ### **...**
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