feat: add sql solution to lc problem: No.1892 (#1116)

No.1892.Page Recommendations II

Author: yanglbme

.github/workflows/clang-format-lint.yml

@@ -10,8 +10,18 @@ jobs:
 
     steps:
     - uses: actions/checkout@v3
+
     - uses: DoozyX/clang-format-lint-action@v0.13
       with:
         source: '.'
         extensions: 'c,cpp,java'
         clangFormatVersion: 12
+        inplace: True
+
+    - uses: EndBug/add-and-commit@v9
+        with:
+          committer_name: yanglbme
+          committer_email: contact@yanglibin.info
+          message: 'chore: format code with clang-format'
+        env:
+          GITHUB_TOKEN: ${{ secrets.ACTION_TOKEN }}

solution/1800-1899/1892.Page Recommendations II/README.md

@@ -127,7 +127,24 @@ Likes 表:
 <!-- 这里可写当前语言的特殊实现逻辑 -->
 
 ```sql
-
+# Write your MySQL query statement below
+WITH
+    S AS (
+        SELECT * FROM Friendship
+        UNION
+        SELECT user2_id, user1_id FROM Friendship
+    )
+SELECT user1_id AS user_id, page_id, count(1) AS friends_likes
+FROM
+    S AS s
+    LEFT JOIN Likes AS l ON s.user2_id = l.user_id
+WHERE
+    NOT EXISTS (
+        SELECT 1
+        FROM Likes AS l2
+        WHERE user1_id = l2.user_id AND l.page_id = l2.page_id
+    )
+GROUP BY user1_id, page_id;
 ```
 
 <!-- tabs:end -->

solution/1800-1899/1892.Page Recommendations II/README_EN.md

@@ -120,7 +120,24 @@ You can recommend pages for users 2, 3, 4, and 5 using a similar process.
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+WITH
+    S AS (
+        SELECT * FROM Friendship
+        UNION
+        SELECT user2_id, user1_id FROM Friendship
+    )
+SELECT user1_id AS user_id, page_id, count(1) AS friends_likes
+FROM
+    S AS s
+    LEFT JOIN Likes AS l ON s.user2_id = l.user_id
+WHERE
+    NOT EXISTS (
+        SELECT 1
+        FROM Likes AS l2
+        WHERE user1_id = l2.user_id AND l.page_id = l2.page_id
+    )
+GROUP BY user1_id, page_id;
 ```
 
 <!-- tabs:end -->

solution/1800-1899/1892.Page Recommendations II/Solution.sql

@@ -0,0 +1,18 @@
+# Write your MySQL query statement below
+WITH
+    S AS (
+        SELECT * FROM Friendship
+        UNION
+        SELECT user2_id, user1_id FROM Friendship
+    )
+SELECT user1_id AS user_id, page_id, count(1) AS friends_likes
+FROM
+    S AS s
+    LEFT JOIN Likes AS l ON s.user2_id = l.user_id
+WHERE
+    NOT EXISTS (
+        SELECT 1
+        FROM Likes AS l2
+        WHERE user1_id = l2.user_id AND l.page_id = l2.page_id
+    )
+GROUP BY user1_id, page_id;