feat: update sql solution to lc problem: No.0585 (#1917)

Author: thinkasany

solution/0500-0599/0585.Investments in 2016/README.md

@@ -84,11 +84,11 @@ WITH
     T AS (
         SELECT
             tiv_2016,
-            COUNT(pid) OVER (PARTITION BY tiv_2015) AS cnt1,
-            COUNT(pid) OVER (PARTITION BY CONCAT(lat, '-', lon)) AS cnt2
+            COUNT(1) OVER (PARTITION BY tiv_2015) AS cnt1,
+            COUNT(1) OVER (PARTITION BY lat, lon) AS cnt2
         FROM Insurance
     )
-SELECT ROUND(IFNULL(SUM(tiv_2016), 0), 2) AS tiv_2016
+SELECT ROUND(SUM(tiv_2016), 2) AS tiv_2016
 FROM T
 WHERE cnt1 > 1 AND cnt2 = 1;
 ```

solution/0500-0599/0585.Investments in 2016/README_EN.md

@@ -77,11 +77,11 @@ WITH
     T AS (
         SELECT
             tiv_2016,
-            COUNT(pid) OVER (PARTITION BY tiv_2015) AS cnt1,
-            COUNT(pid) OVER (PARTITION BY CONCAT(lat, '-', lon)) AS cnt2
+            COUNT(1) OVER (PARTITION BY tiv_2015) AS cnt1,
+            COUNT(1) OVER (PARTITION BY lat, lon) AS cnt2
         FROM Insurance
     )
-SELECT ROUND(IFNULL(SUM(tiv_2016), 0), 2) AS tiv_2016
+SELECT ROUND(SUM(tiv_2016), 2) AS tiv_2016
 FROM T
 WHERE cnt1 > 1 AND cnt2 = 1;
 ```

solution/0500-0599/0585.Investments in 2016/Solution.sql

@@ -3,10 +3,10 @@ WITH
     T AS (
         SELECT
             tiv_2016,
-            COUNT(pid) OVER (PARTITION BY tiv_2015) AS cnt1,
-            COUNT(pid) OVER (PARTITION BY CONCAT(lat, '-', lon)) AS cnt2
+            COUNT(1) OVER (PARTITION BY tiv_2015) AS cnt1,
+            COUNT(1) OVER (PARTITION BY lat, lon) AS cnt2
         FROM Insurance
     )
-SELECT ROUND(IFNULL(SUM(tiv_2016), 0), 2) AS tiv_2016
+SELECT ROUND(SUM(tiv_2016), 2) AS tiv_2016
 FROM T
 WHERE cnt1 > 1 AND cnt2 = 1;