feat: add sql solution to lc problem: No.1729. Find Followers Count

Author: yanglbme

solution/1700-1799/1729.Find Followers Count/README.md

@@ -49,17 +49,26 @@
 
 <p> </p>
 
-
 ## 解法
 
 <!-- 这里可写通用的实现逻辑 -->
 
+`GROUP BY` 实现。
+
 <!-- tabs:start -->
 
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+    user_id, count(1) AS followers_count
+FROM
+    Followers
+GROUP BY
+    user_id
+ORDER BY
+    user_id
 ```
 
-<!-- tabs:end -->
+<!-- tabs:end -->

solution/1700-1799/1729.Find Followers Count/README_EN.md

@@ -49,15 +49,22 @@ The followers of 2 are {0,1}
 
 <p>&nbsp;</p>
 
-
 ## Solutions
 
 <!-- tabs:start -->
 
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+    user_id, count(1) AS followers_count
+FROM
+    Followers
+GROUP BY
+    user_id
+ORDER BY
+    user_id
 ```
 
 <!-- tabs:end -->

solution/1700-1799/1729.Find Followers Count/Solution.sql

@@ -0,0 +1,9 @@
+# Write your MySQL query statement below
+SELECT
+    user_id, count(1) AS followers_count
+FROM
+    Followers
+GROUP BY
+    user_id
+ORDER BY
+    user_id;