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feat: add solutions to lc problem: No.2068
No.2068.Check Whether Two Strings are Almost Equivalent
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‎solution/2000-2099/2068.Check Whether Two Strings are Almost Equivalent/README.md

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Original file line numberDiff line numberDiff line change
@@ -60,22 +60,84 @@
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<!-- 这里可写通用的实现逻辑 -->
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哈希表计数。
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<!-- tabs:start -->
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### **Python3**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```python
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class Solution:
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def checkAlmostEquivalent(self, word1: str, word2: str) -> bool:
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counter = defaultdict(int)
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for c in word1:
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counter[c] += 1
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for c in word2:
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counter[c] -= 1
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return all(abs(x) <= 3 for x in counter.values())
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```
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### **Java**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```java
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class Solution {
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public boolean checkAlmostEquivalent(String word1, String word2) {
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int[] counter = new int[26];
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for (char c : word1.toCharArray()) {
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++counter[c - 'a'];
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}
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for (char c : word2.toCharArray()) {
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--counter[c - 'a'];
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}
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for (int i = 0; i < 26; ++i) {
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if (Math.abs(counter[i]) > 3) {
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return false;
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}
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}
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return true;
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}
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}
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```
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### **C++**
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```cpp
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class Solution {
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public:
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bool checkAlmostEquivalent(string word1, string word2) {
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vector<int> counter(26);
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for (char& c : word1) ++counter[c - 'a'];
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for (char& c : word2) --counter[c - 'a'];
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for (int i = 0; i < 26; ++i)
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if (abs(counter[i]) > 3)
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return 0;
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return 1;
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}
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};
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```
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### **Go**
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```go
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func checkAlmostEquivalent(word1 string, word2 string) bool {
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counter := make([]int, 26)
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for i := range word1 {
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counter[word1[i]-'a']++
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}
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for i := range word2 {
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counter[word2[i]-'a']--
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}
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for _, v := range counter {
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if v > 3 || -v > 3 {
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return false
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}
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}
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return true
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}
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```
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### **...**

‎solution/2000-2099/2068.Check Whether Two Strings are Almost Equivalent/README_EN.md

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@@ -62,13 +62,73 @@ The difference is 4, which is more than the allowed 3.
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### **Python3**
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```python
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class Solution:
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def checkAlmostEquivalent(self, word1: str, word2: str) -> bool:
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counter = defaultdict(int)
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for c in word1:
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counter[c] += 1
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for c in word2:
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counter[c] -= 1
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return all(abs(x) <= 3 for x in counter.values())
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```
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### **Java**
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```java
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class Solution {
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public boolean checkAlmostEquivalent(String word1, String word2) {
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int[] counter = new int[26];
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for (char c : word1.toCharArray()) {
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++counter[c - 'a'];
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}
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for (char c : word2.toCharArray()) {
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--counter[c - 'a'];
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}
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for (int i = 0; i < 26; ++i) {
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if (Math.abs(counter[i]) > 3) {
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return false;
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}
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}
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return true;
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}
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}
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```
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### **C++**
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```cpp
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class Solution {
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public:
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bool checkAlmostEquivalent(string word1, string word2) {
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vector<int> counter(26);
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for (char& c : word1) ++counter[c - 'a'];
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for (char& c : word2) --counter[c - 'a'];
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for (int i = 0; i < 26; ++i)
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if (abs(counter[i]) > 3)
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return 0;
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return 1;
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}
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};
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```
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### **Go**
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```go
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func checkAlmostEquivalent(word1 string, word2 string) bool {
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counter := make([]int, 26)
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for i := range word1 {
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counter[word1[i]-'a']++
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}
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for i := range word2 {
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counter[word2[i]-'a']--
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}
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for _, v := range counter {
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if v > 3 || -v > 3 {
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return false
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}
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}
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return true
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}
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```
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### **...**

‎solution/2000-2099/2068.Check Whether Two Strings are Almost Equivalent/Solution.cpp

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class Solution {
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public:
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bool checkAlmostEquivalent(string word1, string word2) {
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vector<int> counter(26);
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for (char& c : word1) ++counter[c - 'a'];
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for (char& c : word2) --counter[c - 'a'];
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for (int i = 0; i < 26; ++i)
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if (abs(counter[i]) > 3)
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return 0;
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return 1;
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}
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};

‎solution/2000-2099/2068.Check Whether Two Strings are Almost Equivalent/Solution.go

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func checkAlmostEquivalent(word1 string, word2 string) bool {
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counter := make([]int, 26)
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for i := range word1 {
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counter[word1[i]-'a']++
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}
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for i := range word2 {
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counter[word2[i]-'a']--
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}
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for _, v := range counter {
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if v > 3 || -v > 3 {
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return false
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}
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}
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return true
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}

‎solution/2000-2099/2068.Check Whether Two Strings are Almost Equivalent/Solution.java

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class Solution {
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public boolean checkAlmostEquivalent(String word1, String word2) {
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int[] counter = new int[26];
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for (char c : word1.toCharArray()) {
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++counter[c - 'a'];
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}
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for (char c : word2.toCharArray()) {
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--counter[c - 'a'];
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}
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for (int i = 0; i < 26; ++i) {
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if (Math.abs(counter[i]) > 3) {
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return false;
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}
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}
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return true;
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}
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}

‎solution/2000-2099/2068.Check Whether Two Strings are Almost Equivalent/Solution.py

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class Solution:
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def checkAlmostEquivalent(self, word1: str, word2: str) -> bool:
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counter = defaultdict(int)
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for c in word1:
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counter[c] += 1
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for c in word2:
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counter[c] -= 1
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return all(abs(x) <= 3 for x in counter.values())

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