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feat: add solutions to lc problem: No.2144 (#1494)
No.2144.Minimum Cost of Buying Candies With Discount
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‎solution/2100-2199/2144.Minimum Cost of Buying Candies With Discount/README.md

+32-22
Original file line numberDiff line numberDiff line change
@@ -61,6 +61,12 @@
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<!-- 这里可写通用的实现逻辑 -->
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**方法一：贪心**
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我们可以先将糖果按照价格从高到低排序，然后每三个糖果中取两个糖果，这样可以保证免费获得的糖果价格最高，从而使得总开销最小。
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时间复杂度 $O(n \times \log n)$，空间复杂度 $O(\log n)$。其中 $n$ 是糖果数。
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<!-- tabs:start -->
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### **Python3**
@@ -70,13 +76,8 @@
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```python
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class Solution:
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def minimumCost(self, cost: List[int]) -> int:
73-
cost.sort()
74-
ans, n = 0, len(cost)
75-
for i in range(n - 1, -1, -3):
76-
ans += cost[i]
77-
if i >= 1:
78-
ans += cost[i - 1]
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return ans
79+
cost.sort(reverse=True)
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return sum(cost) - sum(cost[2::3])
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```
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### **Java**
@@ -87,10 +88,10 @@ class Solution:
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class Solution {
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public int minimumCost(int[] cost) {
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Arrays.sort(cost);
90-
int ans = 0, n = cost.length;
91-
for (int i = n - 1; i >= 0; i -= 3) {
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int ans = 0;
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for (int i = cost.length - 1; i >= 0; i -= 3) {
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ans += cost[i];
93-
if (i >= 1) {
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if (i > 0) {
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ans += cost[i - 1];
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}
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}
@@ -105,11 +106,13 @@ class Solution {
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class Solution {
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public:
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int minimumCost(vector<int>& cost) {
108-
sort(cost.begin(), cost.end());
109-
int ans = 0, n = cost.size();
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for (int i = n - 1; i >= 0; i -= 3) {
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sort(cost.rbegin(), cost.rend());
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int ans = 0;
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for (int i = 0; i < cost.size(); i += 3) {
111112
ans += cost[i];
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if (i >= 1) ans += cost[i - 1];
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if (i < cost.size() - 1) {
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ans += cost[i + 1];
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}
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}
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return ans;
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}
@@ -119,25 +122,32 @@ public:
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### **Go**
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121124
```go
122-
func minimumCost(cost []int) int {
125+
func minimumCost(cost []int) (ans int) {
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sort.Ints(cost)
124-
ans, n := 0, len(cost)
125-
for i := n - 1; i >= 0; i -= 3 {
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for i := len(cost) - 1; i >= 0; i -= 3 {
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ans += cost[i]
127-
if i >= 1 {
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if i > 0 {
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ans += cost[i-1]
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}
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}
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return ans
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return
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}
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```
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### **TypeScript**
136138

137-
<!-- 这里可写当前语言的特殊实现逻辑 -->
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```ts
140-
140+
function minimumCost(cost: number[]): number {
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cost.sort((a, b) => a - b);
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let ans = 0;
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for (let i = cost.length - 1; i >= 0; i -= 3) {
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ans += cost[i];
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if (i) {
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ans += cost[i - 1];
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}
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}
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return ans;
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}
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```
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### **...**

‎solution/2100-2199/2144.Minimum Cost of Buying Candies With Discount/README_EN.md

+26-20
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@@ -65,13 +65,8 @@ Hence, the minimum cost to buy all candies is 5 + 5 = 10.
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```python
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class Solution:
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def minimumCost(self, cost: List[int]) -> int:
68-
cost.sort()
69-
ans, n = 0, len(cost)
70-
for i in range(n - 1, -1, -3):
71-
ans += cost[i]
72-
if i >= 1:
73-
ans += cost[i - 1]
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return ans
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cost.sort(reverse=True)
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return sum(cost) - sum(cost[2::3])
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```
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### **Java**
@@ -80,10 +75,10 @@ class Solution:
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class Solution {
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public int minimumCost(int[] cost) {
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Arrays.sort(cost);
83-
int ans = 0, n = cost.length;
84-
for (int i = n - 1; i >= 0; i -= 3) {
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int ans = 0;
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for (int i = cost.length - 1; i >= 0; i -= 3) {
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ans += cost[i];
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if (i >= 1) {
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if (i > 0) {
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ans += cost[i - 1];
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}
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}
@@ -98,11 +93,13 @@ class Solution {
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class Solution {
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public:
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int minimumCost(vector<int>& cost) {
101-
sort(cost.begin(), cost.end());
102-
int ans = 0, n = cost.size();
103-
for (int i = n - 1; i >= 0; i -= 3) {
96+
sort(cost.rbegin(), cost.rend());
97+
int ans = 0;
98+
for (int i = 0; i < cost.size(); i += 3) {
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ans += cost[i];
105-
if (i >= 1) ans += cost[i - 1];
100+
if (i < cost.size() - 1) {
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ans += cost[i + 1];
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}
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}
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return ans;
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}
@@ -112,23 +109,32 @@ public:
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### **Go**
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```go
115-
func minimumCost(cost []int) int {
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func minimumCost(cost []int) (ans int) {
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sort.Ints(cost)
117-
ans, n := 0, len(cost)
118-
for i := n - 1; i >= 0; i -= 3 {
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for i := len(cost) - 1; i >= 0; i -= 3 {
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ans += cost[i]
120-
if i >= 1 {
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if i > 0 {
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ans += cost[i-1]
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}
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}
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return ans
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return
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}
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```
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### **TypeScript**
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```ts
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function minimumCost(cost: number[]): number {
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cost.sort((a, b) => a - b);
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let ans = 0;
130+
for (let i = cost.length - 1; i >= 0; i -= 3) {
131+
ans += cost[i];
132+
if (i) {
133+
ans += cost[i - 1];
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}
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}
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return ans;
137+
}
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```
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### **...**

‎solution/2100-2199/2144.Minimum Cost of Buying Candies With Discount/Solution.cpp

+13-11
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@@ -1,12 +1,14 @@
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class Solution {
2-
public:
3-
int minimumCost(vector<int>& cost) {
4-
sort(cost.begin(), cost.end());
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int ans = 0, n = cost.size();
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for (int i = n - 1; i >= 0; i -= 3) {
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ans += cost[i];
8-
if (i >= 1) ans += cost[i - 1];
9-
}
10-
return ans;
11-
}
1+
class Solution {
2+
public:
3+
int minimumCost(vector<int>& cost) {
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sort(cost.rbegin(), cost.rend());
5+
int ans = 0;
6+
for (int i = 0; i < cost.size(); i += 3) {
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ans += cost[i];
8+
if (i < cost.size() - 1) {
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ans += cost[i + 1];
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}
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}
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return ans;
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}
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};

‎solution/2100-2199/2144.Minimum Cost of Buying Candies With Discount/Solution.go

+4-5
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@@ -1,11 +1,10 @@
1-
func minimumCost(cost []int) int {
1+
func minimumCost(cost []int) (ans int) {
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sort.Ints(cost)
3-
ans, n := 0, len(cost)
4-
for i := n - 1; i >= 0; i -= 3 {
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for i := len(cost) - 1; i >= 0; i -= 3 {
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ans += cost[i]
6-
if i >= 1 {
5+
if i > 0 {
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ans += cost[i-1]
87
}
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}
10-
return ans
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return
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}

‎solution/2100-2199/2144.Minimum Cost of Buying Candies With Discount/Solution.java

+12-12
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@@ -1,13 +1,13 @@
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class Solution {
2-
public int minimumCost(int[] cost) {
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Arrays.sort(cost);
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int ans = 0, n = cost.length;
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for (int i = n - 1; i >= 0; i -= 3) {
6-
ans += cost[i];
7-
if (i >= 1) {
8-
ans += cost[i - 1];
9-
}
10-
}
11-
return ans;
12-
}
1+
class Solution {
2+
public int minimumCost(int[] cost) {
3+
Arrays.sort(cost);
4+
int ans = 0;
5+
for (int i = cost.length - 1; i >= 0; i -= 3) {
6+
ans += cost[i];
7+
if (i > 0) {
8+
ans += cost[i - 1];
9+
}
10+
}
11+
return ans;
12+
}
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}

‎solution/2100-2199/2144.Minimum Cost of Buying Candies With Discount/Solution.py

+4-9
Original file line numberDiff line numberDiff line change
@@ -1,9 +1,4 @@
1-
class Solution:
2-
def minimumCost(self, cost: List[int]) -> int:
3-
cost.sort()
4-
ans, n = 0, len(cost)
5-
for i in range(n - 1, -1, -3):
6-
ans += cost[i]
7-
if i >= 1:
8-
ans += cost[i - 1]
9-
return ans
1+
class Solution:
2+
def minimumCost(self, cost: List[int]) -> int:
3+
cost.sort(reverse=True)
4+
return sum(cost) - sum(cost[2::3])

‎solution/2100-2199/2144.Minimum Cost of Buying Candies With Discount/Solution.ts

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1+
function minimumCost(cost: number[]): number {
2+
cost.sort((a, b) => a - b);
3+
let ans = 0;
4+
for (let i = cost.length - 1; i >= 0; i -= 3) {
5+
ans += cost[i];
6+
if (i) {
7+
ans += cost[i - 1];
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}
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}
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return ans;
11+
}

‎solution/2100-2199/2145.Count the Hidden Sequences/README.md

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<ul>
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<li>比方说，<code>differences = [1, -3, 4]</code>&nbsp;，<code>lower = 1</code>&nbsp;，<code>upper = 6</code>&nbsp;，那么隐藏数组是一个长度为 <code>4</code>&nbsp;且所有值都在&nbsp;<code>1</code>&nbsp;和&nbsp;<code>6</code>&nbsp;（包含两者）之间的数组。
15-
1615
<ul>
1716
<li><code>[3, 4, 1, 5]</code> 和&nbsp;<code>[4, 5, 2, 6]</code>&nbsp;都是符合要求的隐藏数组。</li>
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<li><code>[5, 6, 3, 7]</code>&nbsp;不符合要求，因为它包含大于 <code>6</code>&nbsp;的元素。</li>
1918
<li><code>[1, 2, 3, 4]</code>&nbsp;不符合要求，因为相邻元素的差值不符合给定数据。</li>
2019
</ul>
2120
</li>
22-
2321
</ul>
2422

2523
<p>请你返回 <strong>符合</strong>&nbsp;要求的隐藏数组的数目。如果没有符合要求的隐藏数组，请返回 <code>0</code>&nbsp;。</p>

‎solution/2100-2199/2145.Count the Hidden Sequences/README_EN.md

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@@ -10,14 +10,12 @@
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<ul>
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<li>For example, given <code>differences = [1, -3, 4]</code>, <code>lower = 1</code>, <code>upper = 6</code>, the hidden sequence is a sequence of length <code>4</code> whose elements are in between <code>1</code> and <code>6</code> (<strong>inclusive</strong>).
13-
1413
<ul>
1514
<li><code>[3, 4, 1, 5]</code> and <code>[4, 5, 2, 6]</code> are possible hidden sequences.</li>
1615
<li><code>[5, 6, 3, 7]</code> is not possible since it contains an element greater than <code>6</code>.</li>
1716
<li><code>[1, 2, 3, 4]</code> is not possible since the differences are not correct.</li>
1817
</ul>
1918
</li>
20-
2119
</ul>
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2321
<p>Return <em>the number of <strong>possible</strong> hidden sequences there are.</em> If there are no possible sequences, return <code>0</code>.</p>

‎solution/config.py

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2111,
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2117,
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2140,
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2144,
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2178,
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2241,
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2288,

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