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84 | 84 | class Solution:
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85 | 85 | def maxScore(self, nums: List[int]) -> int:
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86 | 86 | m = len(nums)
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| 87 | + f = [0] * (1 << m) |
87 | 88 | g = [[0] * m for _ in range(m)]
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88 | 89 | for i in range(m):
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89 | 90 | for j in range(i + 1, m):
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90 | 91 | g[i][j] = gcd(nums[i], nums[j])
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91 |
| - f = [0] * (1 << m) |
92 | 92 | for k in range(1 << m):
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93 | 93 | if (cnt := k.bit_count()) % 2 == 0:
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94 | 94 | for i in range(m):
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95 | 95 | if k >> i & 1:
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96 | 96 | for j in range(i + 1, m):
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97 | 97 | if k >> j & 1:
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98 |
| - f[k] = max( |
99 |
| - f[k], |
100 |
| - f[k ^ (1 << i) ^ (1 << j)] + cnt // 2 * g[i][j], |
101 |
| - ) |
| 98 | + f[k] = max(f[k], f[k ^ (1 << i) ^ (1 << j)] + cnt // 2 * g[i][j]) |
102 | 99 | return f[-1]
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103 | 100 | ```
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104 | 101 |
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@@ -219,6 +216,52 @@ func gcd(a, b int) int {
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219 | 216 | }
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220 | 217 | ```
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221 | 218 |
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| 219 | +### **TypeScript** |
| 220 | + |
| 221 | +```ts |
| 222 | +function maxScore(nums: number[]): number { |
| 223 | + const m = nums.length; |
| 224 | + const f: number[] = new Array(1 << m).fill(0); |
| 225 | + const g: number[][] = new Array(m).fill(0).map(() => new Array(m).fill(0)); |
| 226 | + for (let i = 0; i < m; ++i) { |
| 227 | + for (let j = i + 1; j < m; ++j) { |
| 228 | + g[i][j] = gcd(nums[i], nums[j]); |
| 229 | + } |
| 230 | + } |
| 231 | + for (let k = 0; k < 1 << m; ++k) { |
| 232 | + const cnt = bitCount(k); |
| 233 | + if (cnt % 2 === 0) { |
| 234 | + for (let i = 0; i < m; ++i) { |
| 235 | + if ((k >> i) & 1) { |
| 236 | + for (let j = i + 1; j < m; ++j) { |
| 237 | + if ((k >> j) & 1) { |
| 238 | + const t = |
| 239 | + f[k ^ (1 << i) ^ (1 << j)] + |
| 240 | + ~~(cnt / 2) * g[i][j]; |
| 241 | + f[k] = Math.max(f[k], t); |
| 242 | + } |
| 243 | + } |
| 244 | + } |
| 245 | + } |
| 246 | + } |
| 247 | + } |
| 248 | + return f[(1 << m) - 1]; |
| 249 | +} |
| 250 | + |
| 251 | +function gcd(a: number, b: number): number { |
| 252 | + return b ? gcd(b, a % b) : a; |
| 253 | +} |
| 254 | + |
| 255 | +function bitCount(i: number): number { |
| 256 | + i = i - ((i >>> 1) & 0x55555555); |
| 257 | + i = (i & 0x33333333) + ((i >>> 2) & 0x33333333); |
| 258 | + i = (i + (i >>> 4)) & 0x0f0f0f0f; |
| 259 | + i = i + (i >>> 8); |
| 260 | + i = i + (i >>> 16); |
| 261 | + return i & 0x3f; |
| 262 | +} |
| 263 | +``` |
| 264 | + |
222 | 265 | ### **...**
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223 | 266 |
|
224 | 267 | ```
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