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33 | 33 |
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34 | 34 | <!-- 这里可写通用的实现逻辑 -->
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35 | 35 |
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| 36 | +前缀和 + 哈希表。 |
| 37 | + |
| 38 | +遍历字符串数组 array,将数字视为 1,字母视为 -1(或者反过来),题目转换为元素和为 0 的最长子数组。 |
| 39 | + |
36 | 40 | <!-- tabs:start -->
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37 | 41 |
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38 | 42 | ### **Python3**
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39 | 43 |
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40 | 44 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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41 | 45 |
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42 | 46 | ```python
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| 47 | +class Solution: |
| 48 | + def findLongestSubarray(self, array: List[str]) -> List[str]: |
| 49 | + seen = {0: -1} |
| 50 | + t = mx = 0 |
| 51 | + ans = [] |
| 52 | + for i, s in enumerate(array): |
| 53 | + t += 1 if s.isalpha() else -1 |
| 54 | + if t in seen: |
| 55 | + if mx < i - seen[t]: |
| 56 | + mx = i - seen[t] |
| 57 | + ans = array[seen[t] + 1: i + 1] |
| 58 | + else: |
| 59 | + seen[t] = i |
| 60 | + return ans |
43 | 61 |
|
44 | 62 | ```
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45 | 63 |
|
|
48 | 66 | <!-- 这里可写当前语言的特殊实现逻辑 -->
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49 | 67 |
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50 | 68 | ```java
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| 69 | +class Solution { |
| 70 | + public String[] findLongestSubarray(String[] array) { |
| 71 | + Map<Integer, Integer> seen = new HashMap<>(); |
| 72 | + seen.put(0, -1); |
| 73 | + int t = 0, mx = 0; |
| 74 | + int j = 0; |
| 75 | + for (int i = 0; i < array.length; ++i) { |
| 76 | + t += Character.isDigit(array[i].charAt(0)) ? 1 : -1; |
| 77 | + if (seen.containsKey(t)) { |
| 78 | + if (mx < i - seen.get(t)) { |
| 79 | + mx = i - seen.get(t); |
| 80 | + j = seen.get(t) + 1; |
| 81 | + } |
| 82 | + } else { |
| 83 | + seen.put(t, i); |
| 84 | + } |
| 85 | + } |
| 86 | + String[] ans = new String[mx]; |
| 87 | + for (int i = 0; i < mx; ++i) { |
| 88 | + ans[i] = array[i + j]; |
| 89 | + } |
| 90 | + return ans; |
| 91 | + } |
| 92 | +} |
| 93 | +``` |
| 94 | + |
| 95 | +### **C++** |
| 96 | + |
| 97 | +```cpp |
| 98 | +class Solution { |
| 99 | +public: |
| 100 | + vector<string> findLongestSubarray(vector<string>& array) { |
| 101 | + unordered_map<int, int> seen; |
| 102 | + seen[0] = -1; |
| 103 | + int t = 0, mx = 0, j = 0; |
| 104 | + for (int i = 0; i < array.size(); ++i) |
| 105 | + { |
| 106 | + t += isdigit(array[i][0]) ? 1 : -1; |
| 107 | + if (seen.count(t)) |
| 108 | + { |
| 109 | + if (mx < i - seen[t]) |
| 110 | + { |
| 111 | + mx = i - seen[t]; |
| 112 | + j = seen[t] + 1; |
| 113 | + } |
| 114 | + } |
| 115 | + else |
| 116 | + { |
| 117 | + seen[t] = i; |
| 118 | + } |
| 119 | + } |
| 120 | + return {array.begin() + j, array.begin() + j + mx}; |
| 121 | + } |
| 122 | +}; |
| 123 | +``` |
51 | 124 |
|
| 125 | +### **Go** |
| 126 | +
|
| 127 | +```go |
| 128 | +func findLongestSubarray(array []string) []string { |
| 129 | + seen := map[int]int{0: -1} |
| 130 | + t, mx, j := 0, 0, 0 |
| 131 | + for i, s := range array { |
| 132 | + if unicode.IsDigit(rune(s[0])) { |
| 133 | + t++ |
| 134 | + } else { |
| 135 | + t-- |
| 136 | + } |
| 137 | + if k, ok := seen[t]; ok { |
| 138 | + if mx < i-k { |
| 139 | + mx = i - k |
| 140 | + j = k + 1 |
| 141 | + } |
| 142 | + } else { |
| 143 | + seen[t] = i |
| 144 | + } |
| 145 | + } |
| 146 | + return array[j : j+mx] |
| 147 | +} |
52 | 148 | ```
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53 | 149 |
|
54 | 150 | ### **...**
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