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solution/0000-0099/0079.Word Search/README.md

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difficulty: 中等
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/0000-0099/0079.Word%20Search/README.md
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tags:
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- 深度优先搜索
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- 数组
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- 字符串
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- 回溯

solution/0000-0099/0079.Word Search/README_EN.md

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difficulty: Medium
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/0000-0099/0079.Word%20Search/README_EN.md
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tags:
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- Depth-First Search
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- Array
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- String
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- Backtracking

solution/0100-0199/0151.Reverse Words in a String/README.md

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<p><strong>示例 1:</strong></p>
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<pre>
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<strong>输入:</strong>s = "<code>the sky is blue</code>"
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<strong>输出:</strong>"<code>blue is sky the</code>"
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<strong>输入:</strong>s = "the sky is blue"
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<strong>输出:</strong>"blue is sky the"
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</pre>
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<p><strong>示例 2:</strong></p>

solution/0100-0199/0153.Find Minimum in Rotated Sorted Array/README.md

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<pre>
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<strong>输入:</strong>nums = [4,5,6,7,0,1,2]
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<strong>输出:</strong>0
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<strong>解释:</strong>原数组为 [0,1,2,4,5,6,7] ,旋转 3 次得到输入数组。
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<strong>解释:</strong>原数组为 [0,1,2,4,5,6,7] ,旋转 4 次得到输入数组。
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</pre>
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<p><strong>示例 3:</strong></p>

solution/0100-0199/0185.Department Top Three Salaries/README.md

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- 山姆的薪水第二高
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- 没有第三高的工资,因为只有两名员工</pre>
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<p>&nbsp;</p>
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<p><strong>提示:</strong></p>
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<ul>
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<li>没有姓名、薪资和部门 <strong>完全</strong> 相同的员工。</li>
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</ul>
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<!-- description:end -->
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## 解法

solution/0100-0199/0185.Department Top Three Salaries/README_EN.md

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- There is no third-highest salary as there are only two employees
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</pre>
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<p>&nbsp;</p>
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<p><strong>Constraints:</strong></p>
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<ul>
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<li>There are no employees with the <strong>exact</strong> same name, salary <em>and</em> department.</li>
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</ul>
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<!-- description:end -->
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## Solutions

solution/0200-0299/0207.Course Schedule/README_EN.md

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<pre>
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<strong>Input:</strong> numCourses = 2, prerequisites = [[1,0]]
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<strong>Output:</strong> true
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<strong>Explanation:</strong> There are a total of 2 courses to take.
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<strong>Explanation:</strong> There are a total of 2 courses to take.
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To take course 1 you should have finished course 0. So it is possible.
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</pre>
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<pre>
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<strong>Input:</strong> numCourses = 2, prerequisites = [[1,0],[0,1]]
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<strong>Output:</strong> false
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<strong>Explanation:</strong> There are a total of 2 courses to take.
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<strong>Explanation:</strong> There are a total of 2 courses to take.
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To take course 1 you should have finished course 0, and to take course 0 you should also have finished course 1. So it is impossible.
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</pre>
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solution/0400-0499/0439.Ternary Expression Parser/README.md

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<p>你可以总是假设给定的表达式是有效的,并且只包含数字,&nbsp;<code>'?'</code>&nbsp;&nbsp;&nbsp;<code>':'</code>&nbsp;&nbsp;&nbsp;<code>'T'</code>&nbsp;和 <code>'F'</code> ,其中 <code>'T'</code> 为真, <code>'F'</code> 为假。表达式中的所有数字都是 <strong>一位</strong> 数(即在 <strong>[0,9] </strong>范围内)。</p>
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<p>条件表达式从右到左分组(大多数语言中都是这样),表达式的结果总是为数字 <code>'T'</code> 或 <code>'F'</code> 。</p>
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<p>条件表达式从右到左分组(大多数语言中都是这样),表达式的结果总是为数字<code>'T'</code> 或 <code>'F'</code> 。</p>
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<p>&nbsp;</p>
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solution/0500-0599/0536.Construct Binary Tree from String/README.md

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<ul>
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<li><code>0 &lt;= s.length &lt;= 3 * 10<sup>4</sup></code></li>
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<li>输入字符串中只包含&nbsp;<code>'('</code>, <code>')'</code>, <code>'-'</code>&nbsp;和&nbsp;<code>'0'</code> ~ <code>'9'</code>&nbsp;</li>
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<li>空树由&nbsp;<code>""</code>&nbsp;而非<code>"()"</code>表示。</li>
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<li>树中所有数字的值 <strong>最多</strong> 不超过&nbsp;<code>2<sup>30</sup></code>。</li>
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</ul>
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<!-- description:end -->

solution/0500-0599/0536.Construct Binary Tree from String/README_EN.md

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<ul>
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<li><code>0 &lt;= s.length &lt;= 3 * 10<sup>4</sup></code></li>
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<li><code>s</code> consists of digits, <code>&#39;(&#39;</code>, <code>&#39;)&#39;</code>, and <code>&#39;-&#39;</code> only.</li>
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<li>All numbers in the tree have value <strong>at most</strong> than <code>2<sup>30</sup></code>.</li>
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</ul>
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<!-- description:end -->

solution/0500-0599/0542.01 Matrix/README_EN.md

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<p>Given an <code>m x n</code> binary matrix <code>mat</code>, return <em>the distance of the nearest </em><code>0</code><em> for each cell</em>.</p>
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<p>The distance between two adjacent cells is <code>1</code>.</p>
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<p>The distance between two cells sharing a common edge is <code>1</code>.</p>
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<p>&nbsp;</p>
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<p><strong class="example">Example 1:</strong></p>
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<li>There is at least one <code>0</code> in <code>mat</code>.</li>
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</ul>
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<p>&nbsp;</p>
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<p><strong>Note:</strong> This question is the same as 1765: <a href="https://leetcode.com/problems/map-of-highest-peak/description/" target="_blank">https://leetcode.com/problems/map-of-highest-peak/</a></p>
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<!-- description:end -->
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## Solutions

solution/0600-0699/0649.Dota2 Senate/README_EN.md

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<pre>
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<strong>Input:</strong> senate = &quot;RD&quot;
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<strong>Output:</strong> &quot;Radiant&quot;
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<strong>Explanation:</strong>
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The first senator comes from Radiant and he can just ban the next senator&#39;s right in round 1.
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And the second senator can&#39;t exercise any rights anymore since his right has been banned.
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<strong>Explanation:</strong>
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The first senator comes from Radiant and he can just ban the next senator&#39;s right in round 1.
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And the second senator can&#39;t exercise any rights anymore since his right has been banned.
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And in round 2, the first senator can just announce the victory since he is the only guy in the senate who can vote.
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</pre>
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<pre>
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<strong>Input:</strong> senate = &quot;RDD&quot;
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<strong>Output:</strong> &quot;Dire&quot;
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<strong>Explanation:</strong>
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The first senator comes from Radiant and he can just ban the next senator&#39;s right in round 1.
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And the second senator can&#39;t exercise any rights anymore since his right has been banned.
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And the third senator comes from Dire and he can ban the first senator&#39;s right in round 1.
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<strong>Explanation:</strong>
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The first senator comes from Radiant and he can just ban the next senator&#39;s right in round 1.
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And the second senator can&#39;t exercise any rights anymore since his right has been banned.
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And the third senator comes from Dire and he can ban the first senator&#39;s right in round 1.
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And in round 2, the third senator can just announce the victory since he is the only guy in the senate who can vote.
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</pre>
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solution/0600-0699/0689.Maximum Sum of 3 Non-Overlapping Subarrays/README.md

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<!-- description:start -->
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<p>给你一个整数数组 <code>nums</code> 和一个整数 <code>k</code> ,找出三个长度为 <code>k</code> 、互不重叠、且全部数字和(<code>3 * k</code> 项)最大的子数组,并返回这三个子数组。</p>
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<p>给你一个整数数组 <code>nums</code> 和一个整数 <code>k</code> ,找出三个长度为 <code>k</code> 、互不重叠、且全部数字和最大的子数组,并返回这三个子数组。</p>
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<p>以下标的数组形式返回结果,数组中的每一项分别指示每个子数组的起始位置(下标从 <strong>0</strong> 开始)。如果有多个结果,返回字典序最小的一个。</p>
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<p>&nbsp;</p>
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<p><strong>示例 1:</strong></p>
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<p><strong class="example">示例 1:</strong></p>
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<pre>
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<strong>输入:</strong>nums = [1,2,1,2,6,7,5,1], k = 2
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<strong>输出:</strong>[0,3,5]
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<strong>解释:</strong>子数组 [1, 2], [2, 6], [7, 5] 对应的起始下标为 [0, 3, 5]。
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也可以取 [2, 1], 但是结果 [1, 3, 5] 在字典序上更大
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也可以取 [2, 1], 但是结果 [1, 3, 5] 在字典序上更小
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</pre>
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<p><strong>示例 2:</strong></p>
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<p><strong class="example">示例 2:</strong></p>
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<pre>
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<strong>输入:</strong>nums = [1,2,1,2,1,2,1,2,1], k = 2

solution/0600-0699/0689.Maximum Sum of 3 Non-Overlapping Subarrays/README_EN.md

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<strong>Input:</strong> nums = [1,2,1,2,6,7,5,1], k = 2
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<strong>Output:</strong> [0,3,5]
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<strong>Explanation:</strong> Subarrays [1, 2], [2, 6], [7, 5] correspond to the starting indices [0, 3, 5].
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We could have also taken [2, 1], but an answer of [1, 3, 5] would be lexicographically larger.
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We could have also taken [2, 1], but an answer of [1, 3, 5] would be lexicographically smaller.
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</pre>
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<p><strong class="example">Example 2:</strong></p>

solution/0700-0799/0731.My Calendar II/README_EN.md

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<strong>Explanation</strong>
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MyCalendarTwo myCalendarTwo = new MyCalendarTwo();
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myCalendarTwo.book(10, 20); // return True, The event can be booked.
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myCalendarTwo.book(50, 60); // return True, The event can be booked.
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myCalendarTwo.book(10, 40); // return True, The event can be double booked.
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myCalendarTwo.book(10, 20); // return True, The event can be booked.
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myCalendarTwo.book(50, 60); // return True, The event can be booked.
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myCalendarTwo.book(10, 40); // return True, The event can be double booked.
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myCalendarTwo.book(5, 15); // return False, The event cannot be booked, because it would result in a triple booking.
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myCalendarTwo.book(5, 10); // return True, The event can be booked, as it does not use time 10 which is already double booked.
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myCalendarTwo.book(25, 55); // return True, The event can be booked, as the time in [25, 40) will be double booked with the third event, the time [40, 50) will be single booked, and the time [50, 55) will be double booked with the second event.

solution/0800-0899/0850.Rectangle Area II/README.md

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<li><code>1 &lt;= rectangles.length &lt;= 200</code></li>
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<li><code>rectanges[i].length = 4</code><meta charset="UTF-8" /></li>
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<li><code>0 &lt;= x<sub>i1</sub>, y<sub>i1</sub>, x<sub>i2</sub>, y<sub>i2</sub>&nbsp;&lt;= 10<sup>9</sup></code></li>
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<li><code>x<sub>i1&nbsp;</sub>&lt;= x<sub>i2</sub></code></li>
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<li><code>y<sub>i1&nbsp;</sub>&lt;= y<sub>i2</sub></code></li>
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<li>所有矩阵面积不为 0。</li>
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</ul>
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<!-- description:end -->

solution/0800-0899/0850.Rectangle Area II/README_EN.md

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<li><code>0 &lt;= x<sub>i1</sub>, y<sub>i1</sub>, x<sub>i2</sub>, y<sub>i2</sub> &lt;= 10<sup>9</sup></code></li>
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<li><code>x<sub>i1 &lt;= </sub>x<sub>i2</sub></code></li>
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<li><code>y<sub>i1 &lt;=</sub> y<sub>i2</sub></code></li>
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<li>All rectangles have non zero area.</li>
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</ul>
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<!-- description:end -->

solution/0900-0999/0962.Maximum Width Ramp/README.md

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tags:
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-
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- 数组
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- 双指针
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- 单调栈
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---
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solution/0900-0999/0962.Maximum Width Ramp/README_EN.md

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tags:
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- Stack
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- Array
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- Two Pointers
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- Monotonic Stack
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---
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solution/0900-0999/0986.Interval List Intersections/README.md

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tags:
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- 数组
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- 双指针
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- 扫描线
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---
910

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<!-- problem:start -->

solution/0900-0999/0986.Interval List Intersections/README_EN.md

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- Array
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- Line Sweep
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---
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<!-- problem:start -->

solution/1100-1199/1120.Maximum Average Subtree/README_EN.md

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<pre>
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<strong>Input:</strong> root = [5,6,1]
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<strong>Output:</strong> 6.00000
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<strong>Explanation:</strong>
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<strong>Explanation:</strong>
3636
For the node with value = 5 we have an average of (5 + 6 + 1) / 3 = 4.
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For the node with value = 6 we have an average of 6 / 1 = 6.
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For the node with value = 1 we have an average of 1 / 1 = 1.

solution/1700-1799/1765.Map of Highest Peak/README.md

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<li><code>isWater[i][j]</code>&nbsp;要么是&nbsp;<code>0</code>&nbsp;,要么是&nbsp;<code>1</code>&nbsp;。</li>
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<li>至少有 <strong>1</strong>&nbsp;个水域格子。</li>
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</ul>
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<strong>注意:</strong>本题与 <a href="https://leetcode.cn/problems/01-matrix/">542</a> 题相同。
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<!-- description:end -->
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solution/1700-1799/1765.Map of Highest Peak/README_EN.md

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<li>There is at least <strong>one</strong> water cell.</li>
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</ul>
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<p>&nbsp;</p>
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<p><strong>Note:</strong> This question is the same as 542: <a href="https://leetcode.com/problems/01-matrix/description/" target="_blank">https://leetcode.com/problems/01-matrix/</a></p>
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<!-- description:end -->
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## Solutions

solution/2400-2499/2466.Count Ways To Build Good Strings/README_EN.md

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<pre>
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<strong>Input:</strong> low = 3, high = 3, zero = 1, one = 1
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<strong>Output:</strong> 8
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<strong>Explanation:</strong>
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One possible valid good string is &quot;011&quot;.
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It can be constructed as follows: &quot;&quot; -&gt; &quot;0&quot; -&gt; &quot;01&quot; -&gt; &quot;011&quot;.
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<strong>Explanation:</strong>
41+
One possible valid good string is &quot;011&quot;.
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It can be constructed as follows: &quot;&quot; -&gt; &quot;0&quot; -&gt; &quot;01&quot; -&gt; &quot;011&quot;.
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All binary strings from &quot;000&quot; to &quot;111&quot; are good strings in this example.
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</pre>
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solution/3000-3099/3083.Existence of a Substring in a String and Its Reverse/README.md

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<!-- description:start -->
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<p>给你一个字符串 <code>s</code> ,请你判断字符串 <code>s</code> 是否存在一个长度为 <code>2</code> 的子字符串,在其反转后的字符串中也出现。</p>
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<p>给你一个字符串 <code>s</code> ,请你判断字符串 <code>s</code> 是否存在一个长度为 <code>2</code> 的子字符串,在 <code>s</code> 反转后的字符串中也出现。</p>
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<p>如果存在这样的子字符串,返回 <code>true</code>;如果不存在,返回 <code>false</code> 。</p>
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solution/3300-3399/3345.Smallest Divisible Digit Product I/README.md

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comments: true
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difficulty: 简单
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3345.Smallest%20Divisible%20Digit%20Product%20I/README.md
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rating: 1235
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source: 第 143 场双周赛 Q1
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tags:
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- 数学
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- 枚举

solution/3300-3399/3345.Smallest Divisible Digit Product I/README_EN.md

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comments: true
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difficulty: Easy
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3345.Smallest%20Divisible%20Digit%20Product%20I/README_EN.md
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rating: 1235
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source: Biweekly Contest 143 Q1
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tags:
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- Math
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- Enumeration

solution/3300-3399/3346.Maximum Frequency of an Element After Performing Operations I/README.md

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comments: true
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difficulty: 中等
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3346.Maximum%20Frequency%20of%20an%20Element%20After%20Performing%20Operations%20I/README.md
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rating: 1864
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source: 第 143 场双周赛 Q2
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tags:
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- 数组
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- 二分查找

solution/3300-3399/3346.Maximum Frequency of an Element After Performing Operations I/README_EN.md

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comments: true
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difficulty: Medium
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3346.Maximum%20Frequency%20of%20an%20Element%20After%20Performing%20Operations%20I/README_EN.md
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rating: 1864
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source: Biweekly Contest 143 Q2
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tags:
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- Array
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- Binary Search

solution/3300-3399/3347.Maximum Frequency of an Element After Performing Operations II/README.md

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rating: 2155
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source: 第 143 场双周赛 Q3
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tags:
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- 数组
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- 二分查找

solution/3300-3399/3347.Maximum Frequency of an Element After Performing Operations II/README_EN.md

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rating: 2155
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source: Biweekly Contest 143 Q3
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tags:
68
- Array
79
- Binary Search

solution/3300-3399/3348.Smallest Divisible Digit Product II/README.md

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rating: 3101
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source: 第 143 场双周赛 Q4
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tags:
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- 贪心
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- 数学

solution/3300-3399/3348.Smallest Divisible Digit Product II/README_EN.md

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rating: 3101
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source: Biweekly Contest 143 Q4
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tags:
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- Greedy
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- Math

solution/3300-3399/3349.Adjacent Increasing Subarrays Detection I/README.md

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rating: 1298
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source: 第 423 场周赛 Q1
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tags:
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- 数组
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---

solution/3300-3399/3349.Adjacent Increasing Subarrays Detection I/README_EN.md

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rating: 1298
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source: Weekly Contest 423 Q1
57
tags:
68
- Array
79
---

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