comments | difficulty | edit_url | rating | source | tags | |||||
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true |
困难 |
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第 287 场周赛 Q4 |
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给你一个字符数组 keys
,由若干 互不相同 的字符组成。还有一个字符串数组 values
,内含若干长度为 2 的字符串。另给你一个字符串数组 dictionary
,包含解密后所有允许的原字符串。请你设计并实现一个支持加密及解密下标从 0 开始字符串的数据结构。
字符串 加密 按下述步骤进行:
- 对字符串中的每个字符
c
,先从keys
中找出满足keys[i] == c
的下标i
。 - 在字符串中,用
values[i]
替换字符c
。
请注意,如果 keys
中不存在字符串中的字符,则无法执行加密过程,返回空字符串 ""
。
字符串 解密 按下述步骤进行:
- 将字符串每相邻 2 个字符划分为一个子字符串,对于每个子字符串
s
,找出满足values[i] == s
的一个下标i
。如果存在多个有效的i
,从中选择 任意 一个。这意味着一个字符串解密可能得到多个解密字符串。 - 在字符串中,用
keys[i]
替换s
。
实现 Encrypter
类:
Encrypter(char[] keys, String[] values, String[] dictionary)
用keys
、values
和dictionary
初始化Encrypter
类。String encrypt(String word1)
按上述加密过程完成对word1
的加密,并返回加密后的字符串。int decrypt(String word2)
统计并返回可以由word2
解密得到且出现在dictionary
中的字符串数目。
示例:
输入: ["Encrypter", "encrypt", "decrypt"] [[['a', 'b', 'c', 'd'], ["ei", "zf", "ei", "am"], ["abcd", "acbd", "adbc", "badc", "dacb", "cadb", "cbda", "abad"]], ["abcd"], ["eizfeiam"]] 输出: [null, "eizfeiam", 2] 解释: Encrypter encrypter = new Encrypter([['a', 'b', 'c', 'd'], ["ei", "zf", "ei", "am"], ["abcd", "acbd", "adbc", "badc", "dacb", "cadb", "cbda", "abad"]); encrypter.encrypt("abcd"); // 返回 "eizfeiam"。 // 'a' 映射为 "ei",'b' 映射为 "zf",'c' 映射为 "ei",'d' 映射为 "am"。 encrypter.decrypt("eizfeiam"); // return 2. // "ei" 可以映射为 'a' 或 'c',"zf" 映射为 'b',"am" 映射为 'd'。 // 因此,解密后可以得到的字符串是 "abad","cbad","abcd" 和 "cbcd"。 // 其中 2 个字符串,"abad" 和 "abcd",在 dictionary 中出现,所以答案是 2 。
提示:
1 <= keys.length == values.length <= 26
values[i].length == 2
1 <= dictionary.length <= 100
1 <= dictionary[i].length <= 100
- 所有
keys[i]
和dictionary[i]
互不相同 1 <= word1.length <= 2000
1 <= word2.length <= 200
- 所有
word1[i]
都出现在keys
中 word2.length
是偶数keys
、values[i]
、dictionary[i]
、word1
和word2
只含小写英文字母- 至多调用
encrypt
和decrypt
总计200
次
我们用一个哈希表
在构造函数中,我们遍历
在加密函数中,我们遍历输入字符串
在解密函数中,我们直接返回
空间复杂度
class Encrypter:
def __init__(self, keys: List[str], values: List[str], dictionary: List[str]):
self.mp = dict(zip(keys, values))
self.cnt = Counter(self.encrypt(v) for v in dictionary)
def encrypt(self, word1: str) -> str:
res = []
for c in word1:
if c not in self.mp:
return ''
res.append(self.mp[c])
return ''.join(res)
def decrypt(self, word2: str) -> int:
return self.cnt[word2]
# Your Encrypter object will be instantiated and called as such:
# obj = Encrypter(keys, values, dictionary)
# param_1 = obj.encrypt(word1)
# param_2 = obj.decrypt(word2)
class Encrypter {
private Map<Character, String> mp = new HashMap<>();
private Map<String, Integer> cnt = new HashMap<>();
public Encrypter(char[] keys, String[] values, String[] dictionary) {
for (int i = 0; i < keys.length; ++i) {
mp.put(keys[i], values[i]);
}
for (String w : dictionary) {
cnt.merge(encrypt(w), 1, Integer::sum);
}
}
public String encrypt(String word1) {
StringBuilder sb = new StringBuilder();
for (char c : word1.toCharArray()) {
if (!mp.containsKey(c)) {
return "";
}
sb.append(mp.get(c));
}
return sb.toString();
}
public int decrypt(String word2) {
return cnt.getOrDefault(word2, 0);
}
}
/**
* Your Encrypter object will be instantiated and called as such:
* Encrypter obj = new Encrypter(keys, values, dictionary);
* String param_1 = obj.encrypt(word1);
* int param_2 = obj.decrypt(word2);
*/
class Encrypter {
public:
unordered_map<string, int> cnt;
unordered_map<char, string> mp;
Encrypter(vector<char>& keys, vector<string>& values, vector<string>& dictionary) {
for (int i = 0; i < keys.size(); ++i) {
mp[keys[i]] = values[i];
}
for (auto v : dictionary) {
cnt[encrypt(v)]++;
}
}
string encrypt(string word1) {
string res = "";
for (char c : word1) {
if (!mp.count(c)) {
return "";
}
res += mp[c];
}
return res;
}
int decrypt(string word2) {
return cnt[word2];
}
};
/**
* Your Encrypter object will be instantiated and called as such:
* Encrypter* obj = new Encrypter(keys, values, dictionary);
* string param_1 = obj->encrypt(word1);
* int param_2 = obj->decrypt(word2);
*/
type Encrypter struct {
mp map[byte]string
cnt map[string]int
}
func Constructor(keys []byte, values []string, dictionary []string) Encrypter {
mp := map[byte]string{}
cnt := map[string]int{}
for i, k := range keys {
mp[k] = values[i]
}
e := Encrypter{mp, cnt}
for _, v := range dictionary {
e.cnt[e.Encrypt(v)]++
}
return e
}
func (this *Encrypter) Encrypt(word1 string) string {
var ans strings.Builder
for _, c := range word1 {
if v, ok := this.mp[byte(c)]; ok {
ans.WriteString(v)
} else {
return ""
}
}
return ans.String()
}
func (this *Encrypter) Decrypt(word2 string) int {
return this.cnt[word2]
}
/**
* Your Encrypter object will be instantiated and called as such:
* obj := Constructor(keys, values, dictionary);
* param_1 := obj.Encrypt(word1);
* param_2 := obj.Decrypt(word2);
*/
class Encrypter {
private mp: Map<string, string> = new Map();
private cnt: Map<string, number> = new Map();
constructor(keys: string[], values: string[], dictionary: string[]) {
for (let i = 0; i < keys.length; i++) {
this.mp.set(keys[i], values[i]);
}
for (const w of dictionary) {
const encrypted = this.encrypt(w);
if (encrypted !== '') {
this.cnt.set(encrypted, (this.cnt.get(encrypted) || 0) + 1);
}
}
}
encrypt(word: string): string {
let res = '';
for (const c of word) {
if (!this.mp.has(c)) {
return '';
}
res += this.mp.get(c);
}
return res;
}
decrypt(word: string): number {
return this.cnt.get(word) || 0;
}
}
/**
* Your Encrypter object will be instantiated and called as such:
* const obj = new Encrypter(keys, values, dictionary);
* const param_1 = obj.encrypt(word1);
* const param_2 = obj.decrypt(word2);
*/