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Description

You are implementing a program to use as your calendar. We can add a new event if adding the event will not cause a triple booking.

A triple booking happens when three events have some non-empty intersection (i.e., some moment is common to all the three events.).

The event can be represented as a pair of integers start and end that represents a booking on the half-open interval [start, end), the range of real numbers x such that start <= x < end.

Implement the MyCalendarTwo class:

  • MyCalendarTwo() Initializes the calendar object.
  • boolean book(int start, int end) Returns true if the event can be added to the calendar successfully without causing a triple booking. Otherwise, return false and do not add the event to the calendar.

 

Example 1:

Input
["MyCalendarTwo", "book", "book", "book", "book", "book", "book"]
[[], [10, 20], [50, 60], [10, 40], [5, 15], [5, 10], [25, 55]]
Output
[null, true, true, true, false, true, true]

Explanation
MyCalendarTwo myCalendarTwo = new MyCalendarTwo();
myCalendarTwo.book(10, 20); // return True, The event can be booked. 
myCalendarTwo.book(50, 60); // return True, The event can be booked. 
myCalendarTwo.book(10, 40); // return True, The event can be double booked. 
myCalendarTwo.book(5, 15);  // return False, The event cannot be booked, because it would result in a triple booking.
myCalendarTwo.book(5, 10); // return True, The event can be booked, as it does not use time 10 which is already double booked.
myCalendarTwo.book(25, 55); // return True, The event can be booked, as the time in [25, 40) will be double booked with the third event, the time [40, 50) will be single booked, and the time [50, 55) will be double booked with the second event.

 

Constraints:

  • 0 <= start < end <= 109
  • At most 1000 calls will be made to book.

Solutions

Python3

from sortedcontainers import SortedDict


class MyCalendarTwo:

    def __init__(self):
        self.sd = SortedDict()

    def book(self, start: int, end: int) -> bool:
        if start not in self.sd:
            self.sd[start] = 0
        if end not in self.sd:
            self.sd[end] = 0
        self.sd[start] += 1
        self.sd[end] -= 1
        s = 0
        for v in self.sd.values():
            s += v
            if s > 2:
                self.sd[start] -= 1
                self.sd[end] += 1
                return False
        return True


# Your MyCalendarTwo object will be instantiated and called as such:
# obj = MyCalendarTwo()
# param_1 = obj.book(start,end)

Java

class MyCalendarTwo {
    private Map<Integer, Integer> tm = new TreeMap<>();

    public MyCalendarTwo() {

    }

    public boolean book(int start, int end) {
        tm.put(start, tm.getOrDefault(start, 0) + 1);
        tm.put(end, tm.getOrDefault(end, 0) - 1);
        int s = 0;
        for (int v : tm.values()) {
            s += v;
            if (s > 2) {
                tm.put(start, tm.get(start) - 1);
                tm.put(end, tm.get(end) + 1);
                return false;
            }
        }
        return true;
    }
}

/**
 * Your MyCalendarTwo object will be instantiated and called as such:
 * MyCalendarTwo obj = new MyCalendarTwo();
 * boolean param_1 = obj.book(start,end);
 */

C++

class MyCalendarTwo {
public:
    map<int, int> m;

    MyCalendarTwo() {

    }

    bool book(int start, int end) {
        ++m[start];
        --m[end];
        int s = 0;
        for (auto& [k, v] : m)
        {
            s += v;
            if (s > 2)
            {
                --m[start];
                ++m[end];
                return false;
            }
        }
        return true;
    }
};

/**
 * Your MyCalendarTwo object will be instantiated and called as such:
 * MyCalendarTwo* obj = new MyCalendarTwo();
 * bool param_1 = obj->book(start,end);
 */

...