你这个学期必须选修 numCourses
门课程,记为 0
到 numCourses - 1
。
在选修某些课程之前需要一些先修课程。 先修课程按数组 prerequisites
给出,其中 prerequisites[i] = [ai, bi]
,表示如果要学习课程 ai
则 必须 先学习课程 bi
。
- 例如,先修课程对
[0, 1]
表示:想要学习课程0
,你需要先完成课程1
。
请你判断是否可能完成所有课程的学习?如果可以,返回 true
;否则,返回 false
。
示例 1:
输入:numCourses = 2, prerequisites = [[1,0]] 输出:true 解释:总共有 2 门课程。学习课程 1 之前,你需要完成课程 0 。这是可能的。
示例 2:
输入:numCourses = 2, prerequisites = [[1,0],[0,1]] 输出:false 解释:总共有 2 门课程。学习课程 1 之前,你需要先完成课程 0 ;并且学习课程 0 之前,你还应先完成课程 1 。这是不可能的。
提示:
1 <= numCourses <= 105
0 <= prerequisites.length <= 5000
prerequisites[i].length == 2
0 <= ai, bi < numCourses
prerequisites[i]
中的所有课程对 互不相同
拓扑排序,BFS 实现。
class Solution:
def canFinish(self, numCourses: int, prerequisites: List[List[int]]) -> bool:
edges = collections.defaultdict(list)
indegree = [0] * numCourses
for i, j in prerequisites:
edges[j].append(i)
indegree[i] += 1
q = collections.deque()
for i in range(numCourses):
if indegree[i] == 0:
q.append(i)
cnt = 0
while q:
i = q.popleft()
cnt += 1
for j in edges[i]:
indegree[j] -= 1
if indegree[j] == 0:
q.append(j)
return cnt == numCourses
class Solution {
public boolean canFinish(int numCourses, int[][] prerequisites) {
List<Integer>[] edges = new List[numCourses];
for (int i = 0; i < numCourses; ++i) {
edges[i] = new ArrayList<>();
}
int[] indegree = new int[numCourses];
for (int[] p : prerequisites) {
edges[p[1]].add(p[0]);
++indegree[p[0]];
}
Queue<Integer> q = new LinkedList<>();
for (int i = 0; i < numCourses; ++i) {
if (indegree[i] == 0) {
q.offer(i);
}
}
int cnt = 0;
while (!q.isEmpty()) {
int i = q.poll();
++cnt;
for (int j : edges[i]) {
--indegree[j];
if (indegree[j] == 0) {
q.offer(j);
}
}
}
return cnt == numCourses;
}
}
class Solution {
public:
bool canFinish(int numCourses, vector<vector<int>>& prerequisites) {
vector<vector<int>> edges(numCourses);
vector<int> indegree(numCourses);
for (auto p : prerequisites)
{
edges[p[1]].push_back(p[0]);
++indegree[p[0]];
}
queue<int> q;
for (int i = 0; i < numCourses; ++i)
{
if (indegree[i] == 0) q.push(i);
}
int cnt = 0;
while (!q.empty())
{
int i = q.front();
q.pop();
++cnt;
for (int j : edges[i])
{
--indegree[j];
if (indegree[j] == 0) q.push(j);
}
}
return cnt == numCourses;
}
};
func canFinish(numCourses int, prerequisites [][]int) bool {
edges := make([][]int, numCourses)
indegree := make([]int, numCourses)
for _, p := range prerequisites {
edges[p[1]] = append(edges[p[1]], p[0])
indegree[p[0]]++
}
var q []int
for i := 0; i < numCourses; i++ {
if indegree[i] == 0 {
q = append(q, i)
}
}
cnt := 0
for len(q) > 0 {
i := q[0]
q = q[1:]
cnt++
for _, j := range edges[i] {
indegree[j]--
if indegree[j] == 0 {
q = append(q, j)
}
}
}
return cnt == numCourses
}
using System.Collections.Generic;
public class Solution {
public bool CanFinish(int numCourses, int[][] prerequisites) {
var indegree = new int[numCourses];
var edgeCount = prerequisites.Length;
var edge = new List<int>[numCourses];
for (var i = 0; i < edgeCount; ++i)
{
var child = prerequisites[i][0];
var parent = prerequisites[i][1];
if (edge[parent] == null)
{
edge[parent] = new List<int>();
}
edge[parent].Add(child);
++indegree[child];
}
var queue = new Queue<int>();
for (var i = 0; i < numCourses; ++i)
{
if (indegree[i] == 0) queue.Enqueue(i);
}
var count = 0;
while (queue.Count > 0)
{
var node = queue.Dequeue();
++count;
if (edge[node] != null)
{
foreach (var next in edge[node])
{
if (--indegree[next] == 0)
{
queue.Enqueue(next);
}
}
}
}
return count == numCourses;
}
}