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Solution.cpp
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
vector<vector<int>> closestNodes(TreeNode* root, vector<int>& queries) {
vector<int> nums;
function<void(TreeNode * root)> dfs = [&](TreeNode* root) {
if (!root) return;
dfs(root->left);
nums.emplace_back(root->val);
dfs(root->right);
};
dfs(root);
vector<vector<int>> ans;
int n = nums.size();
for (int& v : queries) {
int i = upper_bound(nums.begin(), nums.end(), v) - nums.begin() - 1;
int j = lower_bound(nums.begin(), nums.end(), v) - nums.begin();
int mi = i >= 0 && i < n ? nums[i] : -1;
int mx = j >= 0 && j < n ? nums[j] : -1;
ans.push_back({mi, mx});
}
return ans;
}
};