Solution2.java

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public int sumOfLeftLeaves(TreeNode root) {
        if (root == null) {
            return 0;
        }
        Deque<TreeNode> stk = new ArrayDeque<>();
        stk.push(root);
        int ans = 0;
        while (!stk.isEmpty()) {
            root = stk.pop();
            if (root.left != null) {
                if (root.left.left == root.left.right) {
                    ans += root.left.val;
                } else {
                    stk.push(root.left);
                }
            }
            if (root.right != null) {
                stk.push(root.right);
            }
        }
        return ans;
    }
}