Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST.
Calling next()
will return the next smallest number in the BST.
Example:
BSTIterator iterator = new BSTIterator(root); iterator.next(); // return 3 iterator.next(); // return 7 iterator.hasNext(); // return true iterator.next(); // return 9 iterator.hasNext(); // return true iterator.next(); // return 15 iterator.hasNext(); // return true iterator.next(); // return 20 iterator.hasNext(); // return false
Note:
<li><code>next()</code> and <code>hasNext()</code> should run in average O(1) time and uses O(<i>h</i>) memory, where <i>h</i> is the height of the tree.</li>
<li>You may assume that <code>next()</code> call will always be valid, that is, there will be at least a next smallest number in the BST when <code>next()</code> is called.</li>