Your are given an array of positive integers nums
.
Count and print the number of (contiguous) subarrays where the product of all the elements in the subarray is less than k
.
Example 1:
Input: nums = [10, 5, 2, 6], k = 100 Output: 8 Explanation: The 8 subarrays that have product less than 100 are: [10], [5], [2], [6], [10, 5], [5, 2], [2, 6], [5, 2, 6]. Note that [10, 5, 2] is not included as the product of 100 is not strictly less than k.
Note:
0 < nums.length <= 50000
.0 < nums[i] < 1000
.0 <= k < 10^6
.class Solution {
public:
int numSubarrayProductLessThanK(vector<int>& nums, int k) {
int left = 0, right;
long mul = 1;
int count = 0;
for (right = 0; right < nums.size(); right++) {
mul *= nums[right];
while(left <= right && mul >= k) {
mul /= nums[left++];
}
count += right >= left? right - left + 1: 0;
}
return count;
}
};