README_EN.md

1255. Maximum Score Words Formed by Letters

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Description

Given a list of words, list of  single letters (might be repeating) and score of every character.

Return the maximum score of any valid set of words formed by using the given letters (words[i] cannot be used two or more times).

It is not necessary to use all characters in letters and each letter can only be used once. Score of letters 'a', 'b', 'c', ... ,'z' is given by score[0], score[1], ... , score[25] respectively.

 

Example 1:

Input: words = ["dog","cat","dad","good"], letters = ["a","a","c","d","d","d","g","o","o"], score = [1,0,9,5,0,0,3,0,0,0,0,0,0,0,2,0,0,0,0,0,0,0,0,0,0,0]
Output: 23
Explanation:
Score  a=1, c=9, d=5, g=3, o=2
Given letters, we can form the words "dad" (5+1+5) and "good" (3+2+2+5) with a score of 23.
Words "dad" and "dog" only get a score of 21.

Example 2:

Input: words = ["xxxz","ax","bx","cx"], letters = ["z","a","b","c","x","x","x"], score = [4,4,4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,5,0,10]
Output: 27
Explanation:
Score  a=4, b=4, c=4, x=5, z=10
Given letters, we can form the words "ax" (4+5), "bx" (4+5) and "cx" (4+5) with a score of 27.
Word "xxxz" only get a score of 25.

Example 3:

Input: words = ["leetcode"], letters = ["l","e","t","c","o","d"], score = [0,0,1,1,1,0,0,0,0,0,0,1,0,0,1,0,0,0,0,1,0,0,0,0,0,0]
Output: 0
Explanation:
Letter "e" can only be used once.

 

Constraints:

• 1 <= words.length <= 14
• 1 <= words[i].length <= 15
• 1 <= letters.length <= 100
• letters[i].length == 1
• score.length == 26
• 0 <= score[i] <= 10
• words[i], letters[i] contains only lower case English letters.

Solutions

Python3

class Solution:
    def maxScoreWords(
        self, words: List[str], letters: List[str], score: List[int]
    ) -> int:
        cnt = Counter(letters)
        n = len(words)
        ans = 0
        for i in range(1 << n):
            cur = Counter(''.join([words[j] for j in range(n) if i >> j & 1]))
            if all(v <= cnt[c] for c, v in cur.items()):
                t = sum(v * score[ord(c) - ord('a')] for c, v in cur.items())
                ans = max(ans, t)
        return ans

Java

class Solution {
    public int maxScoreWords(String[] words, char[] letters, int[] score) {
        int[] cnt = new int[26];
        for (int i = 0; i < letters.length; ++i) {
            cnt[letters[i] - 'a']++;
        }
        int n = words.length;
        int ans = 0;
        for (int i = 0; i < 1 << n; ++i) {
            int[] cur = new int[26];
            for (int j = 0; j < n; ++j) {
                if (((i >> j) & 1) == 1) {
                    for (int k = 0; k < words[j].length(); ++k) {
                        cur[words[j].charAt(k) - 'a']++;
                    }
                }
            }
            boolean ok = true;
            int t = 0;
            for (int j = 0; j < 26; ++j) {
                if (cur[j] > cnt[j]) {
                    ok = false;
                    break;
                }
                t += cur[j] * score[j];
            }
            if (ok && ans < t) {
                ans = t;
            }
        }
        return ans;
    }
}

C++

class Solution {
public:
    int maxScoreWords(vector<string>& words, vector<char>& letters, vector<int>& score) {
        int cnt[26]{};
        for (char& c : letters) {
            cnt[c - 'a']++;
        }
        int n = words.size();
        int ans = 0;
        for (int i = 0; i < 1 << n; ++i) {
            int cur[26]{};
            for (int j = 0; j < n; ++j) {
                if (i >> j & 1) {
                    for (char& c : words[j]) {
                        cur[c - 'a']++;
                    }
                }
            }
            bool ok = true;
            int t = 0;
            for (int j = 0; j < 26; ++j) {
                if (cur[j] > cnt[j]) {
                    ok = false;
                    break;
                }
                t += cur[j] * score[j];
            }
            if (ok && ans < t) {
                ans = t;
            }
        }
        return ans;
    }
};

Go

func maxScoreWords(words []string, letters []byte, score []int) (ans int) {
	cnt := [26]int{}
	for _, c := range letters {
		cnt[c-'a']++
	}
	n := len(words)
	for i := 0; i < 1<<n; i++ {
		cur := [26]int{}
		for j := 0; j < n; j++ {
			if i>>j&1 == 1 {
				for _, c := range words[j] {
					cur[c-'a']++
				}
			}
		}
		ok := true
		t := 0
		for i, v := range cur {
			if v > cnt[i] {
				ok = false
				break
			}
			t += v * score[i]
		}
		if ok && ans < t {
			ans = t
		}
	}
	return
}

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