multiples_of_3_or_5.cpp

//If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

//Finish the solution so that it returns the sum of all the multiples of 3 or 5 below the number passed in. Additionally, if the number is negative, return 0 (for languages that do have them).

//Note: If the number is a multiple of both 3 and 5, only count it once.

//Courtesy of projecteuler.net (Problem 1)

int solution(int number) 
{
	int sum = 0;
  
  for (int n = 3; n < number; ++n)
  {
  	if ((n % 3 == 0) || (n % 5 == 0))
    	sum += n;
  }

  return sum;
}