-
Notifications
You must be signed in to change notification settings - Fork 215
/
Copy pathstring_halves.cpp
48 lines (37 loc) · 1.28 KB
/
string_halves.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
/*
You are given a string s of even length. Split this string into two halves of equal lengths, and let a be the first half and b be the second half.
Two strings are alike if they have the same number of vowels ('a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'). Notice that s contains uppercase and lowercase letters.
Return true if a and b are alike. Otherwise, return false.
Example 1:
Input: s = "book"
Output: true
Explanation: a = "bo" and b = "ok". a has 1 vowel and b has 1 vowel. Therefore, they are alike.
Example 2:
Input: s = "textbook"
Output: false
Explanation: a = "text" and b = "book". a has 1 vowel whereas b has 2. Therefore, they are not alike.
Notice that the vowel o is counted twice.
Constraints:
2 <= s.length <= 1000
s.length is even.
s consists of uppercase and lowercase letters.
*/
#include<bits/stdc++.h>
class Solution {
public:
bool halvesAreAlike(string s) {
set<char> X {'a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'};
int half = s.size() / 2;
int c = 0, d = 0;
for(int i = 0; i < half; i++){
if(X.find(s[i]) != X.end())
c++;
}
for(int i = half; i < s.size(); i++){
if(X.find(s[i]) != X.end()){
d++;
}
}
return c == d;
}
};