generate-a-string-with-characters-that-have-odd-counts.py

# Given an integer n, return a string with n characters such that each character in such string occurs an odd number of times.
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# The returned string must contain only lowercase English letters. If there are multiples valid strings, return any of them.  
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# Example 1:
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# Input: n = 4
# Output: "pppz"
# Explanation: "pppz" is a valid string since the character 'p' occurs three times and the character 'z' occurs once. Note that there are many other valid strings such as "ohhh" and "love".
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# Example 2:
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# Input: n = 2
# Output: "xy"
# Explanation: "xy" is a valid string since the characters 'x' and 'y' occur once. Note that there are many other valid strings such as "ag" and "ur".
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# Example 3:
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# Input: n = 7
# Output: "holasss"
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# Constraints:
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# 	1 <= n <= 500
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class Solution:
    def generateTheString(self, n: int) -> str:
        if n % 2 == 0:
            return "a"*(n-1) + "b"
        else:
            return "a"*n