sqrtx.py

# Given a non-negative integer x, return the square root of x rounded down to the nearest integer. The returned integer should be non-negative as well.
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# You must not use any built-in exponent function or operator.
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# 	For example, do not use pow(x, 0.5) in c++ or x ** 0.5 in python.
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# Example 1:
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# Input: x = 4
# Output: 2
# Explanation: The square root of 4 is 2, so we return 2.
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# Example 2:
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# Input: x = 8
# Output: 2
# Explanation: The square root of 8 is 2.82842..., and since we round it down to the nearest integer, 2 is returned.
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# Constraints:
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# 	0 <= x <= 231 - 1
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class Solution:
    def mySqrt(self, x: int) -> int:
        n = x
        y = 1
        while(n > y):
            n = (n+y)//2
            y = x//n
        return n