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Time: 39 ms (63.48%), Space: 17.4 MB (7.47%) - LeetHub
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# time complexity: O(t1 + t2)
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# space complexity: O(t1 + t2)
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# Definition for a binary tree node.
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from typing import Optional
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class TreeNode:
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def __init__(self, val=0, left=None, right=None):
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self.val = val
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self.left = left
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self.right = right
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class Solution:
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def leafSimilar(self, root1: Optional[TreeNode], root2: Optional[TreeNode]) -> bool:
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def dfs(node: Optional[TreeNode]):
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if node:
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if not node.left and not node.right:
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yield node.val
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yield from dfs(node.left)
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yield from dfs(node.right)
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return list(dfs(root1)) == list(dfs(root2))
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root1 = TreeNode(1)
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root1.left = TreeNode(2)
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root1.right = TreeNode(3)
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root2 = TreeNode(1)
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root2.left = TreeNode(3)
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root2.right = TreeNode(2)
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print(Solution().leafSimilar(root1, root2))

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