Add files via upload

Author: Somnath-pandit

Q1.sql

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+-- 1. How many times does the average user post?
+
+WITH User_Post_Count AS (
+	SELECT u.id, COUNT(p.id) Post_Count
+    FROM users u 
+    LEFT JOIN photos p 
+    ON u.id = p.user_id
+    GROUP BY u.id 
+)
+
+SELECT AVG(Post_Count) Avg_Posts_Per_User
+FROM User_Post_Count
+

Q10.sql

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+ -- 10.Show the username of each user along with the number 
+ -- of photos they have posted and the number of photos posted by the user
+ -- before them and after them, based on the creation date.
+
+USE ig_clone;
+WITH UserPhotoCounts AS (
+    SELECT
+        u.id,
+        u.username,
+        COUNT(p.id)  photo_count,
+        MIN(p.created_at) first_photo_date
+        
+    FROM users u
+    LEFT JOIN photos p ON u.id = p.user_id
+    GROUP BY u.id, u.username
+),
+UserPhotoCountsPrevNext AS (
+    SELECT
+        upc.*,
+        ROW_NUMBER() OVER (ORDER BY upc.first_photo_date) AS rw_number
+    FROM UserPhotoCounts upc
+)
+
+SELECT
+    upc.username,
+    upc.photo_count,
+    LAG(upc.photo_count) OVER (ORDER BY upc.rw_number) AS prev_photo_count,
+    LEAD(upc.photo_count) OVER (ORDER BY upc.rw_number) AS next_photo_count
+FROM UserPhotoCountsPrevNext upc
+ORDER BY upc.rw_number;

Q2.sql

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+-- 2. Find the top 5 most used hashtags.
+USE ig_clone;
+SELECT tag_name, COUNT(*) tags_count
+FROM tags
+GROUP BY tag_name
+ORDER BY tags_count
+LIMIT 5
+
+

Q3.sql

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+-- 3. Find users who have liked every single photo on the site.
+
+USE ig_clone;
+SELECT u.id, u.username
+FROM users u 
+INNER JOIN photos p 
+	ON u.id = p.user_id
+LEFT JOIN likes l 
+	ON p.id = l.photo_id
+GROUP BY u.id, u.username
+HAVING COUNT(DISTINCT p.id) = COUNT(l.photo_id)
+ORDER BY u.id

Q4.sql

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+-- 4. Retrieve a list of users along with their usernames and the 
+-- rank of their account creation, ordered by the creation date in ascending order.
+
+SELECT *,
+		RANK() OVER (ORDER BY created_at) ac_creation_rank
+FROM users
+ORDER BY created_at

Q5.sql

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+-- 5. List the comments made on photos with their comment texts, 
+-- photo URLs, and usernames of users who posted the comments. Include the comment count for each photo
+USE ig_clone;
+
+SELECT c.comment_text, p.image_url, u.username,
+	   (SELECT COUNT(*) 
+        FROM comments c2 
+        WHERE c2.photo_id = c.photo_id) count_of_comment
+FROM comments c
+INNER JOIN photos p 
+	ON c.user_id = p.user_id
+INNER JOIN users u 
+	ON p.user_id = u.id
+
+

Q6.sql

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+-- 6. For each tag, show the tag name and the number of 
+-- photos associated with that tag. Rank the tags by the number of photos in descending order.
+USE ig_clone;
+
+SELECT t.tag_name, COUNT(pt.photo_id) count_of_photo
+FROM tags t 
+LEFT JOIN photo_tags pt 
+	ON t.id = pt.tag_id 
+GROUP BY t.tag_name
+ORDER BY count_of_photo

Q7.sql

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+-- 7. List the usernames of users who have posted photos along 
+-- with the count of photos they have posted. Rank them by the number of photos in descending order.
+
+
+USE ig_clone;
+SELECT u.username, COUNT(p.id) AS photo_count
+FROM users u
+LEFT JOIN photos p 
+	ON u.id = p.user_id
+GROUP BY u.username
+ORDER BY photo_count DESC;

Q8.sql

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+-- 8. Display the username of each user along with the
+-- creation date of their first posted photo and the creation date of their next posted photo.
+
+USE ig_clone;
+
+WITH UserPhotoDates AS (
+    SELECT
+        p.user_id,
+        MIN(p.created_at)  first_photo_date,
+        LEAD(MIN(p.created_at)) OVER (PARTITION BY p.user_id ORDER BY MIN(p.created_at))  next_photo_date
+    FROM photos p
+    GROUP BY p.user_id
+)
+
+SELECT
+    u.username,
+    upd.first_photo_date,
+    upd.next_photo_date
+FROM users u
+INNER JOIN UserPhotoDates upd
+	ON u.id = upd.user_id;

Q9.sql

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+-- 9. For each comment, show the comment text, the username of the commenter, 
+-- and the comment text of the previous comment made on the same photo.
+
+WITH CommentWithPrevious AS (
+    SELECT
+		u.username AS commenter_username,
+        c1.comment_text AS current_comment_text,
+			LAG(c1.comment_text) OVER (PARTITION BY c1.photo_id ORDER BY c1.created_at) AS previous_comment_text
+    FROM comments c1
+    INNER JOIN users u 
+		ON c1.user_id = u.id
+)
+
+SELECT
+    current_comment_text,
+    commenter_username,
+    previous_comment_text
+FROM
+    CommentWithPrevious;