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| 1 | +#include <iostream> |
| 2 | +#include <vector> |
| 3 | +#include <algorithm> |
| 4 | + |
| 5 | +using namespace std; |
| 6 | + |
| 7 | +const int MAX_N = 1e5 + 5, MAX_ENDS = 2, L = 0, R = 1; |
| 8 | +vector <int> tree[MAX_N]; |
| 9 | +long long maximum_at[MAX_N][MAX_ENDS], left_value[MAX_N], right_value[MAX_N]; |
| 10 | + |
| 11 | +void initialize(int no_of_vertices) |
| 12 | +{ |
| 13 | + for(int i = 1; i <= no_of_vertices; i++) |
| 14 | + { |
| 15 | + tree[i].clear(); |
| 16 | + maximum_at[i][L] = maximum_at[i][R] = 0; |
| 17 | + } |
| 18 | +} |
| 19 | + |
| 20 | +void dfs(int v, int parent_v) |
| 21 | +{ |
| 22 | + for(int child_v : tree[v]) |
| 23 | + { |
| 24 | + if(child_v == parent_v) |
| 25 | + { |
| 26 | + continue; |
| 27 | + } |
| 28 | + |
| 29 | + dfs(child_v, v); |
| 30 | + |
| 31 | + long long using_left_value_at_child = abs(left_value[v] - left_value[child_v]) + maximum_at[child_v][L]; |
| 32 | + long long using_right_value_at_child = abs(left_value[v] - right_value[child_v]) + maximum_at[child_v][R]; |
| 33 | + |
| 34 | + maximum_at[v][L] += max(using_left_value_at_child, using_right_value_at_child); |
| 35 | + |
| 36 | + using_left_value_at_child = abs(right_value[v] - left_value[child_v]) + maximum_at[child_v][L]; |
| 37 | + using_right_value_at_child = abs(right_value[v] - right_value[child_v]) + maximum_at[child_v][R]; |
| 38 | + |
| 39 | + maximum_at[v][R] += max(using_left_value_at_child, using_right_value_at_child); |
| 40 | + } |
| 41 | + |
| 42 | + /*cout << "At " << v << " L = " << left_value[v] << " Maximum = " << maximum_at[v][L] << "\n"; |
| 43 | + cout << "At " << v << " R = " << right_value[v] << " Maximum = " << maximum_at[v][R] << "\n";*/ |
| 44 | +} |
| 45 | + |
| 46 | +void solve() |
| 47 | +{ |
| 48 | + int no_of_vertices; |
| 49 | + cin >> no_of_vertices; |
| 50 | + |
| 51 | + initialize(no_of_vertices); |
| 52 | + |
| 53 | + for(int i = 1; i <= no_of_vertices; i++) |
| 54 | + { |
| 55 | + cin >> left_value[i] >> right_value[i]; |
| 56 | + } |
| 57 | + |
| 58 | + int no_of_edges = no_of_vertices - 1; |
| 59 | + for(int i = 1; i <= no_of_edges; i++) |
| 60 | + { |
| 61 | + int u, v; |
| 62 | + cin >> u >> v; |
| 63 | + |
| 64 | + tree[u].push_back(v); |
| 65 | + tree[v].push_back(u); |
| 66 | + } |
| 67 | + |
| 68 | + dfs(1, 0); |
| 69 | + |
| 70 | + cout << max(maximum_at[1][L], maximum_at[1][R]) << "\n"; |
| 71 | +} |
| 72 | + |
| 73 | +int main() |
| 74 | +{ |
| 75 | + ios_base::sync_with_stdio(false); |
| 76 | + cin.tie(NULL); |
| 77 | + |
| 78 | + int no_of_test_cases; |
| 79 | + cin >> no_of_test_cases; |
| 80 | + |
| 81 | + while(no_of_test_cases--) |
| 82 | + solve(); |
| 83 | + |
| 84 | + return 0; |
| 85 | +} |
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