feat: add solutions to lc problems: No.1119,1132

* No.1119. Remove Vowels from a String
* No.1132. Reported Posts II

Author: yanglbme

solution/1100-1199/1119.Remove Vowels from a String/Solution.ts

@@ -0,0 +1,3 @@
+function removeVowels(s: string): string {
+    return s.replace(/[aeiou]/g, '');
+}

solution/1100-1199/1132.Reported Posts II/README.md

@@ -97,7 +97,21 @@ Removals table:
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+	round( avg( avg_per * 100 ), 2 ) AS average_daily_percent 
+FROM
+	(
+	SELECT
+		count( DISTINCT t2.post_id ) / count( DISTINCT t1.post_id ) AS avg_per 
+	FROM
+		Actions t1
+		LEFT JOIN Removals t2 ON t1.post_id = t2.post_id 
+	WHERE
+		t1.extra = 'spam' 
+	GROUP BY
+	action_date 
+	) t3;
 ```
 
 <!-- tabs:end -->

solution/1100-1199/1132.Reported Posts II/README_EN.md

@@ -92,7 +92,21 @@ Note that the output is only one number and that we do not care about the remove
 ### **SQL**
 
 ```sql
-
+# Write your MySQL query statement below
+SELECT
+	round( avg( avg_per * 100 ), 2 ) AS average_daily_percent 
+FROM
+	(
+	SELECT
+		count( DISTINCT t2.post_id ) / count( DISTINCT t1.post_id ) AS avg_per 
+	FROM
+		Actions t1
+		LEFT JOIN Removals t2 ON t1.post_id = t2.post_id 
+	WHERE
+		t1.extra = 'spam' 
+	GROUP BY
+	action_date 
+	) t3;
 ```
 
 <!-- tabs:end -->

solution/1100-1199/1132.Reported Posts II/Solution.sql

@@ -0,0 +1,15 @@
+# Write your MySQL query statement below
+SELECT
+	round( avg( avg_per * 100 ), 2 ) AS average_daily_percent 
+FROM
+	(
+	SELECT
+		count( DISTINCT t2.post_id ) / count( DISTINCT t1.post_id ) AS avg_per 
+	FROM
+		Actions t1
+		LEFT JOIN Removals t2 ON t1.post_id = t2.post_id 
+	WHERE
+		t1.extra = 'spam' 
+	GROUP BY
+	action_date 
+	) t3;

solution/1100-1199/1137.N-th Tribonacci Number/README.md

@@ -44,7 +44,7 @@ T_4 = 1 + 1 + 2 = 4
 
 **方法一：动态规划**
 
-由于题目中给出的递推式，可以使用动态规划求解。
+根据题目中给出的递推式，我们可以使用动态规划求解。
 
 我们定义三个变量 $a$, $b$, $c$，分别表示 $T_{n-3}$, $T_{n-2}$, $T_{n-1}$，初始值分别为 $0$, $1$, $1$。
 

solution/1100-1199/1141.User Activity for the Past 30 Days I/README.md

@@ -72,14 +72,15 @@ Activity table:
 
 ```sql
 SELECT
-    activity_date AS day,
-    COUNT(DISTINCT user_id) AS active_users
+	activity_date AS DAY,
+	COUNT( DISTINCT user_id ) AS active_users 
 FROM
-    Activity
+	Activity 
 WHERE
-    DATEDIFF('2019-07-27', activity_date) < 30
+	DATEDIFF( '2019-07-27', activity_date ) > 0 
+	AND DATEDIFF( '2019-07-27', activity_date ) < 30 
 GROUP BY
-    activity_date;
+	activity_date;
 ```
 
 <!-- tabs:end -->

solution/1100-1199/1141.User Activity for the Past 30 Days I/README_EN.md

@@ -68,14 +68,15 @@ Activity table:
 
 ```sql
 SELECT
-    activity_date AS day,
-    COUNT(DISTINCT user_id) AS active_users
+	activity_date AS DAY,
+	COUNT( DISTINCT user_id ) AS active_users 
 FROM
-    Activity
+	Activity 
 WHERE
-    DATEDIFF('2019-07-27', activity_date) < 30
+	DATEDIFF( '2019-07-27', activity_date ) > 0 
+	AND DATEDIFF( '2019-07-27', activity_date ) < 30 
 GROUP BY
-    activity_date;
+	activity_date;
 ```
 
 <!-- tabs:end -->

solution/1100-1199/1141.User Activity for the Past 30 Days I/Solution.sql

@@ -1,9 +1,10 @@
 SELECT
-    activity_date AS day,
-    COUNT(DISTINCT user_id) AS active_users
+	activity_date AS DAY,
+	COUNT( DISTINCT user_id ) AS active_users 
 FROM
-    Activity
+	Activity 
 WHERE
-    DATEDIFF('2019-07-27', activity_date) < 30
+	DATEDIFF( '2019-07-27', activity_date ) > 0 
+	AND DATEDIFF( '2019-07-27', activity_date ) < 30 
 GROUP BY
-    activity_date;
+	activity_date;