Design a Leaderboard class, which has 3 functions:
addScore(playerId, score)
: Update the leaderboard by addingscore
to the given player's score. If there is no player with such id in the leaderboard, add him to the leaderboard with the givenscore
.top(K)
: Return the score sum of the topK
players.reset(playerId)
: Reset the score of the player with the given id to 0 (in other words erase it from the leaderboard). It is guaranteed that the player was added to the leaderboard before calling this function.
Initially, the leaderboard is empty.
Example 1:
Input: ["Leaderboard","addScore","addScore","addScore","addScore","addScore","top","reset","reset","addScore","top"] [[],[1,73],[2,56],[3,39],[4,51],[5,4],[1],[1],[2],[2,51],[3]] Output: [null,null,null,null,null,null,73,null,null,null,141] Explanation: Leaderboard leaderboard = new Leaderboard (); leaderboard.addScore(1,73); // leaderboard = [[1,73]]; leaderboard.addScore(2,56); // leaderboard = [[1,73],[2,56]]; leaderboard.addScore(3,39); // leaderboard = [[1,73],[2,56],[3,39]]; leaderboard.addScore(4,51); // leaderboard = [[1,73],[2,56],[3,39],[4,51]]; leaderboard.addScore(5,4); // leaderboard = [[1,73],[2,56],[3,39],[4,51],[5,4]]; leaderboard.top(1); // returns 73; leaderboard.reset(1); // leaderboard = [[2,56],[3,39],[4,51],[5,4]]; leaderboard.reset(2); // leaderboard = [[3,39],[4,51],[5,4]]; leaderboard.addScore(2,51); // leaderboard = [[2,51],[3,39],[4,51],[5,4]]; leaderboard.top(3); // returns 141 = 51 + 51 + 39;
Constraints:
1 <= playerId, K <= 10000
- It's guaranteed that
K
is less than or equal to the current number of players. 1 <= score <= 100
- There will be at most
1000
function calls.
from sortedcontainers import SortedList
class Leaderboard:
def __init__(self):
self.d = defaultdict(int)
self.rank = SortedList()
def addScore(self, playerId: int, score: int) -> None:
if playerId not in self.d:
self.d[playerId] = score
self.rank.add(score)
else:
self.rank.remove(self.d[playerId])
self.d[playerId] += score
self.rank.add(self.d[playerId])
def top(self, K: int) -> int:
return sum(self.rank[-K:])
def reset(self, playerId: int) -> None:
self.rank.remove(self.d.pop(playerId))
# Your Leaderboard object will be instantiated and called as such:
# obj = Leaderboard()
# obj.addScore(playerId,score)
# param_2 = obj.top(K)
# obj.reset(playerId)
class Leaderboard {
private Map<Integer, Integer> d = new HashMap<>();
private TreeMap<Integer, Integer> rank = new TreeMap<>((a, b) -> b - a);
public Leaderboard() {
}
public void addScore(int playerId, int score) {
d.merge(playerId, score, Integer::sum);
int newScore = d.get(playerId);
if (newScore != score) {
rank.merge(newScore - score, -1, Integer::sum);
}
rank.merge(newScore, 1, Integer::sum);
}
public int top(int K) {
int ans = 0;
for (var e : rank.entrySet()) {
int score = e.getKey(), cnt = e.getValue();
cnt = Math.min(cnt, K);
ans += score * cnt;
K -= cnt;
if (K == 0) {
break;
}
}
return ans;
}
public void reset(int playerId) {
int score = d.remove(playerId);
if (rank.merge(score, -1, Integer::sum) == 0) {
rank.remove(score);
}
}
}
/**
* Your Leaderboard object will be instantiated and called as such:
* Leaderboard obj = new Leaderboard();
* obj.addScore(playerId,score);
* int param_2 = obj.top(K);
* obj.reset(playerId);
*/
class Leaderboard {
public:
Leaderboard() {
}
void addScore(int playerId, int score) {
d[playerId] += score;
int newScore = d[playerId];
if (newScore != score) {
rank.erase(rank.find(newScore - score));
}
rank.insert(newScore);
}
int top(int K) {
int ans = 0;
for (auto& x : rank) {
ans += x;
if (--K == 0) {
break;
}
}
return ans;
}
void reset(int playerId) {
int score = d[playerId];
d.erase(playerId);
rank.erase(rank.find(score));
}
private:
unordered_map<int, int> d;
multiset<int, greater<int>> rank;
};
/**
* Your Leaderboard object will be instantiated and called as such:
* Leaderboard* obj = new Leaderboard();
* obj->addScore(playerId,score);
* int param_2 = obj->top(K);
* obj->reset(playerId);
*/