feat: 203.remove-linked-list-elements add Python3 implementation (azl397985856#124)

Author: ybian19

problems/203.remove-linked-list-elements.md

@@ -33,13 +33,13 @@ if (!next || next.val !== val) {
 
 ```
 
-
 ## 代码
 
-```js
-
+* 语言支持：JS，Python
 
+Javascript Code:
 
+```js
 /*
  * @lc app=leetcode id=203 lang=javascript
  *
@@ -54,14 +54,14 @@ if (!next || next.val !== val) {
  * Testcase Example:  '[1,2,6,3,4,5,6]\n6'
  *
  * Remove all elements from a linked list of integers that have value val.
- * 
+ *
  * Example:
- * 
- * 
+ *
+ *
  * Input:  1->2->6->3->4->5->6, val = 6
  * Output: 1->2->3->4->5
- * 
- * 
+ *
+ *
  */
 /**
  * Definition for singly-linked list.
@@ -95,6 +95,26 @@ var removeElements = function(head, val) {
 
     return dummy.next;
 };
-
 ```
 
+Python Code:
+
+```python
+# Definition for singly-linked list.
+# class ListNode:
+#     def __init__(self, x):
+#         self.val = x
+#         self.next = None
+
+class Solution:
+    def removeElements(self, head: ListNode, val: int) -> ListNode:
+        prev = ListNode(0)
+        prev.next = head
+        cur = prev
+        while cur.next:
+            if cur.next.val == val:
+                cur.next = cur.next.next
+            else:
+                cur = cur.next
+        return prev.next
+```