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‎Exercise01/Exercise01.ipynb

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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"1. Define a list called ssn with four integer members"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 1,
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"ssn"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"3. Access the first element from list_1"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 3,
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"ssn[0]"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"Access the fourth element from ssn"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 4,
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"ssn[3] "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"4. Access the last element from list_1"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 5,
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"ssn[len(ssn) - 1]"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"5. Access the last element from list_1"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 6,
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"ssn[-1]"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"6. Access the first three elements from list_1 "
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]
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},
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{
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"cell_type": "code",
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"execution_count": 7,
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"ssn[1:3]"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"7. Access the last two elements from list_1"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 8,
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"ssn[-2:]"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"8. Access the first two elements using backward indices"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 9,
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"ssn[:-2]"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"9. Reverse the elements in the list"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 10,

‎Exercise02/Exercise02.ipynb

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"ssn_2 "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"2.Generate a list"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 14,
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"ssn_3 "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"3. Use a while loop"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 15,
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" i += 1 "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"4. find the elements with a 5 in them"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 17,
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"numbers "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"5. Generate a list by adding the two lists"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 19,
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"ssn_5 "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"6. Generate a list by extending a list"
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]
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},
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"cell_type": "code",
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"ssn_2 "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"7. use a nested loop over two lists"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 23,
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" for y in ssn_5: \n",
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" print(str(x) + ' , ' + str(y)) "
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": []
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}
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],
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"metadata": {

‎Exercise03/Exercise03.ipynb

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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"1. Iterate over a list"
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]
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},
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" print(i)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"2. Check whether the integers 25 and -45 are in the list using the in operator"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 8,
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"source": [
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" \"Mustang\" in list_1 "
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": []
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}
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],
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"metadata": {

‎Exercise04/Exercise04.ipynb

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"list_1 "
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"2. We can use the reverse method directly"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 3,
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"list_1.reverse() \n",
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"list_1 "
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {},
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"outputs": [],
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"source": []
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}
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],
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"metadata": {

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