code added

Author: Bharat2044

09_returnLengthOfArgumentsPassed.js

@@ -0,0 +1,68 @@
+// Question Link: https://leetcode.com/problems/return-length-of-arguments-passed/?envType=study-plan-v2&envId=30-days-of-javascript
+// Solution Link: https://leetcode.com/problems/return-length-of-arguments-passed/solutions/5434940/3-javascript-easy-solution-using-one-line-for-loop-and-foreach-loop/
+
+/*
+2703. Return Length of Arguments Passed
+
+Write a function argumentsLength that returns the count of arguments passed to it.
+ 
+Example 1:
+Input: args = [5]
+Output: 1
+Explanation:
+argumentsLength(5); // 1
+One value was passed to the function so it should return 1.
+
+Example 2:
+Input: args = [{}, null, "3"]
+Output: 3
+Explanation: 
+argumentsLength({}, null, "3"); // 3
+Three values were passed to the function so it should return 3.
+
+Constraints:
+args is a valid JSON array
+0 <= args.length <= 100
+*/
+
+
+/**
+ * @param {...(null|boolean|number|string|Array|Object)} args
+ * @return {number}
+ */
+
+/*
+// Approach 1: Using for Loop - TC = O(n), SC = O(1)
+var argumentsLength = function(...args) {
+    let count = 0;
+
+    for (let i = 0; i < args.length; i++) {
+        count++;
+    }
+
+    return count;
+};
+*/
+
+// Approach 2: Using forEach Loop - TC = O(n), SC = O(1)
+var argumentsLength = function(...args) {
+    let count = 0;
+
+    args.forEach((num) => {
+        count++;
+    });
+    
+    return count;
+};
+
+
+/*
+// Approach 3: Using Predefined `length` Method - TC = O(n), SC = O(1)
+var argumentsLength = function(...args) {
+    return args.length;
+};
+*/
+
+/**
+ * argumentsLength(1, 2, 3); // 3
+ */