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Update 0977.有序数组的平方.md
python3 version of brutal force
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problems/0977.有序数组的平方.md

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@@ -39,6 +39,15 @@ public:
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}
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};
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```
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```python3
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class Solution:
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def sortedSquares(self, nums: List[int]) -> List[int]:
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res=[]
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for num in nums:
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res.append(num**2)
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return sorted(res)
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```
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这个时间复杂度是 O(n + nlogn), 可以说是O(nlogn)的时间复杂度,但为了和下面双指针法算法时间复杂度有鲜明对比,我记为 O(n + nlog n)。
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