Merge pull request youngyangyang04#1619 from zhicheng-lee/zhicheng-lee-patch-4

更新 0135.分发糖果.md Java代码

Author: youngyangyang04

problems/0135.分发糖果.md

@@ -135,25 +135,22 @@ class Solution {
          2、起点下标 ratings.length - 2 从右往左， 只要左边 比 右边 大，此时 左边的糖果应该 取本身的糖果数（符合比它左边大） 和 右边糖果数 + 1 二者的最大值，这样才符合 它比它左边的大，也比它右边大
     */
     public int candy(int[] ratings) {
-        int[] candyVec = new int[ratings.length];
+        int len = ratings.length;
+        int[] candyVec = new int[len];
         candyVec[0] = 1;
-        for (int i = 1; i < ratings.length; i++) {
-            if (ratings[i] > ratings[i - 1]) {
-                candyVec[i] = candyVec[i - 1] + 1;
-            } else {
-                candyVec[i] = 1;
-            }
+        for (int i = 1; i < len; i++) {
+            candyVec[i] = (ratings[i] > ratings[i - 1]) ? candyVec[i - 1] + 1 : 1;
         }
 
-        for (int i = ratings.length - 2; i >= 0; i--) {
+        for (int i = len - 2; i >= 0; i--) {
             if (ratings[i] > ratings[i + 1]) {
                 candyVec[i] = Math.max(candyVec[i], candyVec[i + 1] + 1);
             }
         }
 
         int ans = 0;
-        for (int s : candyVec) {
-            ans += s;
+        for (int num : candyVec) {
+            ans += num;
         }
         return ans;
     }